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Vladimir [108]
3 years ago
14

What is completely factored form of x^4+8x^2-9

Mathematics
2 answers:
BabaBlast [244]3 years ago
5 0

Answer: B would be the correct answer on edg. (X+1)(x-1)(x^2+9)

olganol [36]3 years ago
4 0
X^4 + 8x^2 - 9 
= (x^2 + 9)(x^2 - 1)
= (x^2 + 9)(x + 1)(x - 1)  Answer
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<img src="https://tex.z-dn.net/?f=x%20%20%5Cdiv%203x%20-%202%20%3D%201%20%5Cdiv%203x%20-%204" id="TexFormula1" title="x \div 3x
Maurinko [17]

Hello from MrBillDoesMath!

Answer:

x = 1/2 (1 +\- i sqrt(23))

Discussion:

x \3x - 2 =   (x/3)*x - 2   =  (x^2)/3 - 2     (*)

1 \3x - 4   =  (1/3)x - 4                               (**)

(*) = (**)   =>

(x^2)/3 -2 = (1/3)x - 4        => multiply both sides by 3

x^2 - 6 = x - 12                 => subtract x from both sides

x^2 -x -6 = -12                   => add 12 to both sides

x^2-x +6  = 0

Using the quadratic formula gives:

x = 1/2 (1 +\- i sqrt(23))

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MrB

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