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Oxana [17]
3 years ago
15

Help my homework pls!!!!!!​

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

(2x^2 + x-3)/(4x^2-9)

Step-by-step explanation:

The denominator looks like an expression in which we have applied the difference of two squares to

In that case, we know that;

a^2-b^2 = (a-b)(a+ b)

That means we would be have 2x + 3 as the other denominator factor and the expression at the denominator would be;

(2x + 3)(2x-3) = 4x^2 - 9

Also, we would have to cancel out 2x + 3 from the numerator too, so as to be left with only the binomial

That means;

(2x+3)(x-1) = 2x^2-2x+ 3x - 3 = 2x^2+x -3

So we have the original expression as;

(2x^2 + x-3)/(4x^2-9)

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The carnival committee has purchased 985 small prizes. The prizes are to be divided equally among the 29 game booths
Vladimir [108]

Answer:

1 The first digit of the quotient is 3

2. 34 prizes per booth

3.  19 prizes left over

Step-by-step explanation:

We need to divide 985 by 29


29 goes into 98   3 times

29*3 = 87  with 13 left over

135 divided by 29

29*4 =116  135-116 =19

985÷29 = 34  with 19 left over

7 0
3 years ago
(2/5,-2/5),(-7/8,-3/5)
Misha Larkins [42]

Answer: (-19/80, -1/2)

Step By Step Explanation:

First you want to do 2/5 - 7/8. Once you get -19/40, you want to divide it by 2. After doing this step, you will get -19/80. Next, you want to do the same thing with the other one. -2/5 -3/5 or 2/5+3/5 except the answer will be negative. Now you get -1/2. Therefore, the answer is (-19/80, -1/2). Sorry if my explanation is trashy.

3 0
3 years ago
Estimate first. Then give the exact product 3x2.5=?​
julsineya [31]

Answer:

7.5

Step-by-step explanation:

multiply like normal math . then add the decimal point after 1 number

3 0
3 years ago
Read 2 more answers
Answer the questions in the picture ​
Nutka1998 [239]

Answer:

1a 3800, 1b 6300 1c 5100

2a 2630, 2b 2600, 2c 3000

3a 4000, 3b 3000, 3c 8000

7 0
3 years ago
Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allow
jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

 \left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right     i^{3}

Step-by-step explanation:

selecting the first team from n people we have \left(\begin{array}{ccc}n\\1\\\end{array}\right)  = n possibility and choosing second team from the rest of n-1 people we have \left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1

As { A, B} = {B , A}

Therefore, the total possibility is \frac{n(n-1)}{2}

Since our choices are allowed to overlap, the second team is \frac{n(n-1)}{2}

Possibility of choosing both teams will be

\frac{n(n-1)}{2}  *  \frac{n(n-1)}{2}  \\\\= [\frac{n(n-1)}{2}] ^{2}

We now have the formula

1³ + 2³ + ........... + n³ =[\frac{n(n+1)}{2}] ^{2}

1³ + 2³ + ............ + (n-1)³ = [x^{2} \frac{n(n-1)}{2}] ^{2}

=\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] =   [\frac{n(n-1)}{2}]^{3}

4 0
3 years ago
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