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Oxana [17]
3 years ago
15

Help my homework pls!!!!!!​

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

(2x^2 + x-3)/(4x^2-9)

Step-by-step explanation:

The denominator looks like an expression in which we have applied the difference of two squares to

In that case, we know that;

a^2-b^2 = (a-b)(a+ b)

That means we would be have 2x + 3 as the other denominator factor and the expression at the denominator would be;

(2x + 3)(2x-3) = 4x^2 - 9

Also, we would have to cancel out 2x + 3 from the numerator too, so as to be left with only the binomial

That means;

(2x+3)(x-1) = 2x^2-2x+ 3x - 3 = 2x^2+x -3

So we have the original expression as;

(2x^2 + x-3)/(4x^2-9)

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In Leakwater township, there are two plumbers. On a particular day three Leakwater residents call village plumbers independently
Marianna [84]

Answer:

25% probability that all three residents will choose the same plumbe

Step-by-step explanation:

For each resident, there are only two possible outcomes. Either they choose the first plumbe, or they choose the second. The plumbers are chosen independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Each resident randomly chooses one of the two plumbers.

This means that p = \frac{1}{2} = 0.5

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This means that n = 3

What is the probability that all three residents will choose the same plumb

This is P(X = 0)(all choose the second pumble) or P(X = 3)(all choose the first pumble). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.5)^{0}.(0.5)^{3} = 0.125

P(X = 3) = C_{3,3}.(0.5)^{3}.(0.5)^{0} = 0.125

p = P(X = 0) + P(X = 3) = 2*0.125 = 0.25

25% probability that all three residents will choose the same plumbe

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x< 3+4\: and\\\left | 3-4 \right |

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2. Keeping in mind this a Pythagorean Triple, then x=5

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5

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