Help my homework pls!!!!!!

Mathematics

1 answer:

Hitman42 [59]2 years ago

4 0

Answer:

(2x^2 + x-3)/(4x^2-9)

Step-by-step explanation:

The denominator looks like an expression in which we have applied the difference of two squares to

In that case, we know that;

a^2-b^2 = (a-b)(a+ b)

That means we would be have 2x + 3 as the other denominator factor and the expression at the denominator would be;

(2x + 3)(2x-3) = 4x^2 - 9

Also, we would have to cancel out 2x + 3 from the numerator too, so as to be left with only the binomial

That means;

(2x+3)(x-1) = 2x^2-2x+ 3x - 3 = 2x^2+x -3

So we have the original expression as;

(2x^2 + x-3)/(4x^2-9)

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Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$