We're minimizing

subject to

. Using Lagrange multipliers, we have the Lagrangian

with partial derivatives

Set each partial derivative equal to 0:

Subtracting the second equation from the first, we find

Similarly, we can determine that

and

by taking any two of the first three equations. So if

determines a critical point, then

So the smallest value for the sum of squares is

when

.
You put all x on left side and numercial on the right side
13x-12x = 4+4
x = 8
Y=1/2x+6
Y-2=1/2(x+8)
Then simplify and get y by itself
Answer:
3 (10-a) = 4 i think
Step-by-step explanation: