3 years ago

How many ways can a team of 22 hockey players choose a captain and two alternate captains?

Mathematics

1 answer:

Juliette [100K]3 years ago

3 0

You can write down 22 names but them in a box and there is a 1 out of 22 percent chance that each player will pick once

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Mkey [24]

Answer: $\frac{6}{25}$

In this case, we're asked to pick one of 12 blue popsicles out of a bag of 50 – from this, we can just write that the probability of picking a blue popsicle is 12/50. Simplifying this, we can divide both the numerator and denominator by 2 to get our final answer of $\frac{6}{25}$

Hope this helped you!

Step-by-step explanation:

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252miles
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Korolek [52]

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3 years ago

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Which equation(s) have x = –3 as the solution? log3(2x + 15) = 2 log5(8x + 9) = 2 log4(–20x + 4) = 3 logx81 = 4

baherus [9]

Answer:

log_3(2x+15)=2 and log_4(-20x+4)=3

Step-by-step explanation:

Plug it in and see!

$log_3(2x+15)=2\\log_3(2(-3)+15)=2\\log_3(-6+15)=2\\log_3(9)=2\\\text{ This is a true equation because } 3^2=9\\\\\\log_5(8(-3)+9)=2\\log_5(-24+9)=2\\log_5(-15)=2\\\\\text{ Not true because you cannot do log of a negative number }\\\\log_4(-20(-3)+4)=3\\log_4(64)=3\\\text{ this is true because } 4^3=64\\\\\\log_x (81)=4\\log_{-3}(81)=4\\\text{ the base cannot be negative }\\\\\\\\\text{ There is only two options here} \\\\log_3(2x+15)=2 \text{ and } log_4(-20x+4)=3$

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3 years ago

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