A frequency distribution table is a table that summarizes data in two columns.
The result does not appear to have a normal distribution.
<h3>How to construct the frequency distribution table</h3>
From the dataset, we have the following classes using 5 classes with a lower class limit of 119.4 and a class width of 0.2 volts
119.4 - 119.6, 119.7 - 119.9, 120.0 - 120.2. 120.3 - 120.5. and 120.6 - 120.8
So, the frequency distribution table is:
<u>Class Frequency</u>
119.4 - 119.6 4
119.7 - 119.9 10
120.0 - 120.2 6
120.3 - 120.5 5
120.6 - 120.8 0
The result does not appear to be normal.
This is so, because the frequency table do not go in form of a bell shape
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To find the solution to the given expression, we simply isolate the unknown variable m and perform the necessary operations. The solution is as follows.
(3/5)*(2m-10) = (2/3)*m + 10
15*[(3/5)*(2m-10) = (2/3)*m + 10]
9(2m-10) = 10m + 150
18m-90 =10m + 150
18m - 10m = 150 + 90
8m = 240
m = 240/8
m = 30
First, we multiply the whole expression to the least common denominator (LCD) which is 15. Multiplication and division were then performed accordingly. The terms containing the variable m were transposed to the left side of the equation. Mathematical operations were then applied to get the final value of m which is equal to 30.
Answer: x = 38, y = 81, z = 75
Step-by-step explanation:
First, because it's a quadrilateral, we know that (z - 3) + 108 + (y - 9) + (3x - 6) = 360.
Then, we also know that (3x - 6) = 108, because in a parallelogram the two opposite angles are congruent. So, we know that x = 38.
Next, we also know that (z - 3) = (y - 9), because (again) the opposite angles are congruent. But since there are 2 variables and 1 equation, we cannot solve it yet.
But, we also know that (y - 9) + (3x - 6) = 180, because the same side angles are supplementary. We already know that (3x - 6) = 108, so (y - 9) = 180 - 108 = 72. y = 81.
Then, we can also figure out (z - 3) because it's the same as (y - 9), so (z - 3) = 72. z = 75.
So, x = 38 degrees, y = 81 degrees, and z = 75 degrees.
<em>P.S. If this is wrong, please tell me! I'll try my best to fix it. </em>
Yes, the triangles are congruent if AB ≅ DE.
Criteria for the Congruency of two Triangles
If two triangles share the same sides and angles, they are said to be congruent triangles.
Triangles are tested for congruence using the following 4 criteria:
1) Angle-side-angle(ASA): Two angles and a side of a triangle are congruent if they are equal to two angles and the corresponding side of another triangle.
2) Side-side-side(SSS): Two triangles make congruent triangles if all three sides of one triangle are equal to three sides of another.
3) Side angle side(SAS): A triangle is congruent if its two sides and any included angles are equivalent to those of another triangle's two sides and corresponding angle.
4) Hypotenuse - leg(HL): If a triangle's hypotenuse and one of its legs are equal, then the triangle's hypotenuse and leg are also equal.
Checking for Congruency in the Given Triangles
ΔDEF and ABC have a equal angles, ∠F=∠B, as well as a pair of equal sides, DF = AC.
Thus, in order to satisfy the SAS criterion of congruent triangles, AB = DE
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they are the same. they are = (equal)