Is it 5+7+11 ???????????????????????????
We know that sin2x=2sinxcosx
(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
To calculate the remaining number of teams, use the sequence formula:
a(n) = a(1)Rⁿ-¹
Where a(n) and a(1) are the nth and first terms. R is the factor. Therefore, 24 teams is valid value.
After 5 rounds :
a(5) = 128*(½)⁴
a(5) = 128/16 = 8
8 teams are remained.
Answer:C
Step-by-step explanation: The quotient is correct because 27 tenths divided by 3 is 0.9 and 12 hundredths divided by 3 is 0.04
Answer:
3.
141592653589793238462643383279502884197169399375105
82097494459230781640628620899862803482534211706798
21480865132823066470938446095505822317253594081284
81117450284102701938521105559644622948954930381964
42881097566593344612847564823378678316527120190914
5648566923460348610454326648213393607260249141273
Step-by-step explanation:
:)
