The number of bananas required to make the third scale balance is 3.
<h3>What is a scale?</h3>
A scale is a tool used for weighting objects. If the objects on each side weigh the same the scale is balanced. Based on this, let's determine the possible weight of each fruit to balance the last scale.
- Scale 1 (10 bananas/ 2 pineapples)
It is known 10 bananas weigh as much as 2 apples, but to solve this problem let's assume 10 bananas weigh a total of 1000 grams.
- 10 banans = 1000 grams = each banana weighs 100 grams
- 2 pineapples = 1000 grams = each pineapple weighs 500 grams
Scale 2 ( 1 pineapple / 2 bananas, 1 apple)
Using the same imaginary weights let's find the weight of the apple.
- 1 pineapple = 500 grams
- 2 bananas = 200 grams
- 1 apple = 300 grams (500 - 200 = 300)
Scale 3 (1 apple /x )
We know 1 apple is equal to 300 grams and 1 banana is equal to 100 grams. Based on this, the number of bananas to balance the scale is 3.
Learn more about balance in: brainly.com/question/7181548
I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
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Below are the choices that can be found from other source:
A.$340
<span>B.$1560 </span>
<span>C.$38 </span>
<span>D.$1862</span>
Below is the solution:
78000 x .0.02=1560
<span>1900 - 1560=340</span>