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BigorU [14]
3 years ago
8

Write the sum of the numbers as the product of their gcf and another sum Problem: 30+54

Mathematics
1 answer:
omeli [17]3 years ago
4 0
The correct answer here is that the sum has to be 84. This is due to the fact that 30 + 54 is 84, and the greatest common factor is 6 because the factors of 30 are 1, 2, 3, 5, 6 , 10, 15, and 54's Factors: 1, 2, 3, 6, 9, 18, 27, and 54, so from this we can see that 6 is the great common factor.
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Is this table proportional or non-proportional?
tatyana61 [14]

Answer:

in my opinon, this table is proportional

5 0
3 years ago
In triangle XYZ, m∠Z > m∠X + m∠Y. Which must be true about △XYZ?
Solnce55 [7]
Since z is GREATER THAN two angles in the triangle it must be obtuse..
meaning it is GREATER THAN 90 degrees this means that the other two angles cannot equal 90 degrees they have to be less

m∠X + m∠Y < 90°
4 0
3 years ago
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Write the following number in standard form: 3.471 × 10^−5
muminat
0.00003471 is the correct answer I believe
4 0
3 years ago
Consider the arithmetic sequence:
prisoha [69]

Answer:

<em>Answer: D</em>

Step-by-step explanation:

<u>Arithmetic Sequences </u>

The arithmetic sequences are those where any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

a_n=a_1+(n-1)r

Where

an = nth term

a1 = first term

r   = common difference

n  = number of the term

We are given the arithmetic sequence:

10, 12, 14, 16, ...

Where a1=10 and

r = 12 - 10 = 2

Thus the general term is:

a_n=10+(n-1)2

Operating:

a_n=10+2n-2

a_n=8+2n

Answer: D

4 0
3 years ago
Read 2 more answers
he life of light bulbs is distributed normally. The variance of the lifetime is 625 and the mean lifetime of a bulb is 540 hours
almond37 [142]

Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 540, \sigma = \sqrt{625} = 25

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{569 - 540}{25}

Z = 1.16

Z = 1.16 has a p-value of 0.877.

0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

8 0
2 years ago
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