Answer:
The correct options are;
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A
Step-by-step explanation:
Here we have for City A
Maximum - Minimum = 10
Interquartile range =3
City B
Maximum - Minimum = 18.5
Interquartile range =9.5
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.
Answer:
there is a solution
w= -2
Step-by-step explanation:
4w+4=-4
-4 -4
4w=-8
/4 /4
w=-2
Answer:
Step-by-step explanation:
1 Simplify 19-7 to 12.
12^2−8×3+4×3−5
2 Simplify 12^2 to 144
144−8×3+4×3−5
3 Simplify 8×3 to 24.
144−24+4×3−5
4 Simplify 4×3 to 12.
144−24+12−5
5 Simplify 144-24 to 120.
120+12-5
6 Simplify 120+12 to 132.
132-5
7 Simplify.
127
5/8 * 4/5
= 1/8 * 4/1
= 1/4 * 2/1
1/2 * 1/1
Final answer = 1/2
