8 goes with 3/5: 10 goes with n (n being the number of cups)

Use cross products and we get 8n = 6
Now divide by 8
<u>8n</u> = <u>6
</u><u />8 8
n= 6/8 or 3/4 of a cup of flour.
Suppose that the farmer had bought the rice at x dollars per bag and had sold them at a 25% markup. How much did the bags cost him before he added the markup? 1.25x =$75 results in $75/1.25, or $60 per bag.
If he sold 25 bags, his profit would be 1.25($60/bag)(25 bags) = $1875.
I very seriously doubt that the rice was $7500 per bag. Perhaps you meant $75/bag...?
Answer:
b
Step-by-step explanation:
We know that the law of sines states that:

For simplicity, let:

In triangle A1BC this leads to:

Therefore:

Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have: