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12345 [234]
2 years ago
8

Abril and Alanis put some money into their money boxes every week. The amounts of money (y), in dollars, in their money boxes af

ter certain amounts of time (x), in weeks, are shown by the equations below:
Abril
y = 50x + 10

Alanis
y = 30x + 70

After how many weeks will Abril and Alanis have the same amount of money in their money boxes, and what will that amount be? (1 point)


3 weeks, $160

3 weeks, $210

4 weeks, $160

4 weeks, $210
Mathematics
1 answer:
AnnZ [28]2 years ago
8 0

Answer:

  • A. 3 weeks, $160

Step-by-step explanation:

If the value of y is same for both then we have equal right sides of equations

  • 50x + 10 = 30x + 70

Solve this for x

  • 50x - 30x = 70 - 10
  • 20x = 60
  • x = 60/20
  • x = 3

Find the value of y

  • y = 50*3 + 10 = 150 + 10 = 160

Correct choice is A

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Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two
mafiozo [28]

Answer:

The difference of the original two-digit number and the number with reversed digits is 18.

Step-by-step explanation:

Since it's a two digit number, let x represent the tens digit and let y represent the units digit.

Thus, the original two digit number is;

10x + y.

The reverse two digit number is;

10y + x.

We are told that five times the sum of the digits of the two-digit number is 13 less than the original number.

Thus;

5(x + y) = (10x + y) - 13

Multiplying out the bracket gives;

5x + 5y = 10x + y - 13

Rearranging gives;

10x - 5x + y - 5y = 13

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Also,we are told that, four times the sum of its two digits is 21 less than the reversed two-digit number. Thus;

4(x + y) = (10y + x) - 21 - - - (4)

Simplifying gives;

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Answer:

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Step-by-step explanation:

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