In a dihybrid cross for round and yellow seeds (RrYy x RrYy), what is the probability of having green and wrinkled seeds? Key: R
= round r = wrinkled Y = yellow y = green 1:16 3:16 8:16 9:16
2 answers:
The correct option is option (a) 1:16.
The probability of having green and wrinkled seeds in a dihybrid cross for round and yellow seeds is 1:16.
A dihybrid cross is a cross between two different genes that differ in two obeserved traits. A phenotype in a dihybrid cross refers to the physical character exhibited by the organism and the genotype refers to the genetic composition of the organism.
A dihybrid cross for round and yellow seeds can be represented as follows. The phenotype of the parents is plants with round and yellow seeds. Their genotype is RrYy. The gametes formes would be RY, Ry, rY and ry.
Parents - RrYy X RrYy
Gametes - RY, Ry, rY, ry.
A punnette square is a tabular summary of the possible combinations of the paternal and maternal alleles and thus predicting the genotypes of the organisms in a breeding experiment.
With the help of Punnett square for the above cross involving round and yellow seeded plants, the probablilty of genotypes of the organisms in the cross is as follows-
9:16 are the plants exhibiting the phenotype round and yellow.
3:16 are the plants exhibiting the phenotype round and green.
3:16 are the plants exhibiting the phenotype wrinkled and yellow.
1:16 are the plants exhibiting the phenotype wrinkled and green.
Thus, 1:16 is the probability of having a green and wrinkled seeds in a dihybrid cross for round and yellow seeds.
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