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3 years ago

Kite ABCD is similar to kite IJKL. Angle B is congruent to the measure of angle ___.

2 answers:

8 0

Similarity implies correspondence. Angles are listed in the order in which they are congruent to one another. A is congruent to I, B is congruent to J, C is congruent to K, D is congruent to L.

Andreas93 [3]3 years ago

4 0

If two shapes are similar, they are named with corresponding vertex in order.

<em>For example, if 2 triangles are similar and A is same angle as P, B is same angle as Q, and C is same angle as R, we would write </em>

<em>Triangle ABC is similar to Triangle PQR (in order of how they are corresponding to each other)</em>

Given kite ABCD is similar to Kite IJKL, we know that A is same as I, B is same as J, C is same as K, and L is same as D. Hence, angle B is same as angle J. Answer choice B is correct.

ANSWER: B

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Tom went shopping he bought 35 apples that was 50% of what was on the shelf how many apples are on the Shelf

lyudmila [28]

Answer:

70?

Step-by-step explanation:

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3 years ago

The function y = –16t2 + 224 models the height y in feet of a stone t seconds after it is dropped from the edge of a vertical cl

vodomira [7]

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3 years ago

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In a simple regression analysis (where y is a dependent and x an independent variable), if the slope is positive, then it must b

Scorpion4ik [409]

Answer:

c. there is a positive correlation in-between x and y

Step-by-step explanation:

A regression line is a line that suggests that all the points in a scatter diagram lie on or near one particular line. In a simple regression analysis in which y is the dependent variable and x is the independent variable. If the slope is positive, the bivariate data is also said to have a positive correlation. The positive correlation in-between two variables x and y implies that in general, an increase in x goes hand in hand with an increase in y.

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3 years ago

Please help!!

sveta [45]

For this case we have the following equation:
$d = \sqrt{\frac{3h}{2}}$
Where,
d: the distance they can see in thousands
h: their eye-level height in feet
For Kaylib:
$d = \sqrt{\frac{3(48)}{2}}$
$d=\sqrt{3(24)}$
$d=\sqrt{72}$
$d=6\sqrt{2}$
For Addison:
$d = \sqrt{\frac{3(85\frac{1}{3})}{2}}$
$d = \sqrt{\frac{256}{2}}$
$d=\sqrt{128}$
$d=8\sqrt{2}$
Subtracting both distances we have:
$8\sqrt{2} - 6\sqrt{2} = 2\sqrt{2}$
Answer:
$2\sqrt{2}$
B. 2√2 mi

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3 years ago

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7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54

Levart [38]

$7\sqrt3-4\sqrt6+\sqrt{48}-\sqrt{54}\\\\=7\sqrt3-4\sqrt6+\sqrt{16\cdot3}-\sqrt{9\cdot6}\\\\=7\sqrt3-4\sqrt6+\sqrt{16}\cdot\sqrt3-\sqrt9\cdot\sqrt6\\\\=7\sqrt3-4\sqrt6+4\sqrt3-3\sqrt6\\\\=\boxed{11\sqrt3-7\sqrt6}$

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3 years ago