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2 years ago

Kahn academy question:

Mathematics

1 answer:

Rufina [12.5K]2 years ago

8 0

Answer:

2.97×10³

Step-by-step explanation:

3600 - 6.3×10² = 3600 -6.3×100 = 3600 -630 = 2970

= 2.97×1000

= 2.97×10³

_____

Your calculator can accept and display numbers in scientific notation.

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Explain how to use mental math to express 12/25 as a percent

o-na [289]

Answer:

Step-by-step explanation:

12/25 =

12 ÷ 25 =

0.48 =

0.48 × 100/100 =

0.48 × 100% =

(0.48 × 100)% =

48%;

8 0

3 years ago

TVs are measured by

kondor19780726 [428]

Answer:

Step-by-step explanation:

Diagonal is 60 inches, height is 24 inches so

60^2 = 24^2 + width^2

6.25 inches

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2 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago

What are the solutions to the quadratic equation 98-x2=0

kifflom [539]

$98-x^2=0\qquad\text{add}\ x^2\ \text{to both sides}\\\\98=x^2\to x^2=98\\\\x=\pm\sqrt{98}\\\\x=\pm\sqrt{49\cdot2}\\\\x=\pm\sqrt{49}\cdot\sqrt2\\\\\boxed{x=-7\sqrt2\ \vee\ x=7\sqrt2}$