Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
by <u>AAS</u>
Step-by-step explanation:
According to the following two triangles,
and
are congruent by <u>Angle-Angle-Side</u> (AAS), because there are two angles shown and share a side, which is in the middle between triangles.
Answer:
1005
Step-by-step explanation:
If you just kept subtracting from 2580 then the next and then the next number you would get 1005