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3 years ago

HELP PLEASE ASAP! BRAINLIESTTTT

Mathematics

1 answer:

erik [133]3 years ago

4 0

1.) Which variable did you plot on the x-axis, and which variable did you plot on the y-axis?
x-axis represents people's arms span, y-axis represents their corresponding height

2.) Explain why you assigned the variables in that way.
because you can find the height of people(y) by plugging arm span in x. And i can find people's arm span(x) by plugging height as y

You might be interested in

How many hours will it take a culture of bacteria to increase from 20 to 2000 if the growth rate per hour is 85%

Eddi Din [679]

So you are seeing how much time it'll take so you solve for "t", the time.
So you take the formula A=Pe^(rt) 
A=2000 because it's the end value 
P=20 because it's the starting value 
r=.85 since 85%=.85 and .85 is the rate 
Plug the values in and you get 2000=20e^(.85t) 
What you do is you divide by 20 so you get 100=e^(.85t) 
Take the natural logarithm of both sides 'cause of e and a natural log is written as ln so you get 
ln 100=.85t ln e and because you can use the power rule you end up with .85t ln e and 
ln e=1 so you have ln 100 = .85t so you divide by .85 so (ln 100)/.85=t and t=5.4178472776331 
hours 
3. Exponential decay: 
A= Pe^(rt) 
where 
A is the final amount 
P is the initial value 
r is rate of decay 
t is time (years) 
Let's say x is the initial amount then (1/2)x=xe^(32r) 
I used x because the value isn't given but anyway division by x would give you 1/2=e^(32r) 
Take the ln of both sides so ln 1/2=32r ln e and then ln e=1 so ln 1/2=32r. 
Divide both sides by 32 and you'd get (ln 1/2)/32=r and r= -0.021660849392498 
4. Another depreciation question. 
Each year the item retains 88% of its last-year value. 
Solve: 250,000(0.88)^x = 100,000 
0.88^x = 0.4 
x = [log0.4]/[log0.88] 
x = 7.168 years

8 0

3 years ago

Find the volume (in terms of pi) of a sphere of its surface area is 400 pi ft2

elixir [45]

$\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2\qquad \qquad \implies \stackrel{SA}{400\pi }=4\pi r^2\implies \cfrac{400\pi }{4\pi }=r^2 \\\\\\ 100=r^2\implies \sqrt{100}=r\implies \boxed{10=r} \\\\\\ \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\qquad \qquad V=\cfrac{4\pi \boxed{10^3}}{3}\implies V=\cfrac{4000\pi }{3}$

8 0

3 years ago

Read 2 more answers

Help me on question one

Sonja [21]

8*3 1/4
8*13/4
(8*13)/4
104/4
$26

Hope this helps :)

6 0

3 years ago

Sketch the sinusoidal function that passes through (0,-6) , has a period of 12 and an amplitude of 3

riadik2000 [5.3K]

The sinusoidal function that passes through (0,-6), has a period of 12 and an amplitude of 3 will be y = 3 sin 12x - 6.

What is a sinusoidal Function?

It is a function that repeats itself in a particular time interval.

The equation is given as

y = Asin (ωx + Ф) + k

We have

Amplitude (A) = 3

Period (ω) = 12

Phase difference (Ф) = 0

Then the equation will be

y = 3 sin 12x + k

The function is passing through (0, -6). Then we have

-6 = 3sin (12 × 0) + k

-6 = k

Then the equation will be

y = 3 sin 12x - 6

More about the sine function link is given below.

brainly.com/question/3876065

#SPJ1

4 0

2 years ago

A bag contains 11 blocks numbered from 1 to 11. Two blocks are selected from the bag at the same time. (order does not matter) L

melamori03 [73]

Answer:

(A) n(Eᶜ)=40

Step-by-step explanation:

The Sample Space for is given as:

(1,2),(1,3),(1,4),(1,5),(1,6),(1,7),(1,8),(1,9),(1,10),(1,11)

(2,3),(2,4),(2,5),(2,6),(2,7),(2,8),(2,9),(2,10),(2,11)

(3,4),(3,5),(3,6),(3,7),(3,8),(3,9),(3,10),(3,11)

(4,5),(4,6),(4,7),(4,8),(4,9),(4,10),(4,11)

(5,6),(5,7),(5,8),(5,9),(5,10),(5,11)

(6,7),(6,8),(6,9),(6,10),(6,11)

(7,8),(7,9),(7,10),(7,11)

(8,9),(8,10),(8,11)

(9,10),(9,11)

(10,11)

n(S)=55

Event E is the Event that the two numbers are odd.

Therefore: Complement of E will be the event that any of the two numbers is even.

The Sample Space of the complement of E is:

$(1,2),(1,4),(1,6),(1,8),(1,10)\\(2,3),(2,4),(2,5),(2,6),(2,7),(2,8),(2,9),(2,10),(2,11)\\(3,4),(3,6),(3,8),(3,10)\\(4,5),(4,6),(4,7),(4,8),(4,9),(4,10),(4,11)\\(5,6),(5,8),(5,10)\\(6,7),(6,8),(6,9),(6,10),(6,11)\\(7,8),(7,10)\\(8,9),(8,10),(8,11)\\(9,10)\\(10,11)\\$

Therefore:

n(Eᶜ)=40

5 0

4 years ago