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3 years ago

Can someone please help me with this

Mathematics

1 answer:

dedylja [7]3 years ago

5 0

Step-by-step explanation:

WYXV is quadrilateral.

the reason are the undefined angles at W and V (they are equal, but not necessarily 90°, so the shape could shrink or extend between W and V)

ABCD is a rectangle.

AB and CD are parallel and equally long. and C is 90°.

that means then that the other angles must be 90° too, or either the parallel or equally long criteria would be violated.

PQSR is a parallelogram.

PQ and RS are parallel and equally long.

that means that PR and QS must also be parallel and equally long. we just don't know the angles, they could be anything. and therefore this is not a rectangle but a more generic parallelogram.

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Cynthia Besch wants to buy a rug for a room that is 19 ft wide and 32 ft long. She wants to leave a uniform strip of floor aroun

Rainbow [258]

Answer:

The rug should be 15 ft wide and 28 ft long.

Step-by-step explanation:

I have attached a figure that represents the situation.

The the rug is $l$ by $h$ , the width of the strip of floor is $w$ .

We are told that Cynthia can only afford 420 square feet of carpeting; therefore, it must be that

$l*h=420$ <em>(this says the area of the rug must be 420 square feet)</em>

From the figure we see that

$l= 32-2w$

$h=19-2w$

Therefore,

$l*h=420\\\\(32-2w)(19-2w)=420$

We expand this equation and get:

$4w^2-102w+608=420\\\\4w^2-102w+188=0$

using the quadratic equation we get two solutions:

$w=2\\w=23.5$

since the second solution, namely $w=23.5$ , is larger than one of the dimensions of the room (is greater than 19 ft) it cannot be the width of the strip; therefore, we take $w=2$ to be our solution.

Now we find the dimensions of the rug:

$l=32-2(2)=28\\\\h=19-2(2)=15$

The rug is 15 ft wide and 28 ft long.

8 0

4 years ago

Expand and simplify 2(2x+3)+(5x+4)

LekaFEV [45]

2(2x+3)+(5x+4) simplified would be 4x+6+5x+4 and if you add those together you get 9x+10. Hope I helped! if you have any questions just leave a comment

4 0

3 years ago

Read 2 more answers

Which ordered pairs are in the solution set of the system of linear inequalities? y > x y < x + 1 (5, –2), (3, 1), (–4, 2)

steposvetlana [31]

To check which ordered pair (point) is in the solution set of the system of given linear inequalities y>x, y<x+1; we just need to plug given points into both inequalities and check if that point satisfies both inequalities or not. If any point satisfies both inequalities then that point will be in solution.

I will show you calculation for (5,-2)

plug into y>x

-2>5

which is clearly false.

plug into y<x+1

-2<5+1

or -2<6

which is also false.

hence (5,-2) is not in the solution.

Same way if you test all the given points then you will find that none of the given points are satisfying both inequalities.

Hence answer will be "No Solution from given choices".

5 0