15) factor out cos: cos(x)(sin(x)+1)=0
Now this is true when either cos(x)=0 (x=pi/2 and 3pi/2)
Or when sin(x)=-1 (x=3pi/2)
So it's solutions are pi/2 and 3pi/2
okay well usually what I would tell you would be to use the ABC method. you would multiply A (2) by C (6) to get twelve. so you need two numbers that multiply to twelve and add to -4 (the B value). but there are no numbers that fit this description so you have to use the GCF method instead
for this method you must find the GCF for all three numbers which in this case is 2. 2(x^2-2x+3) all these numbers are now prime so this is the factored form
<span>The area in the right tail more extreme than z= 3.01 in a standard normal distribution is given by
P(z > 3.01) = 1 - P(z < 3.01) = 1 - 0.99869 = 0.00131
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