Question

How do i put f(x) = -x^2 + 8x + 9 in vertex form?

Answer 1

Vertex form is y=a(x-h)²+k

complete the square


f(x)=(-x²+8x)+9
undistribute -1
f(x)=-1(x²-8x)+9
take 1/2 of -8 and square it to get 16, then add neagative and positive inside
f(x)=-1(x²-8x+16-16)+9
complete the square
f(x)=-1((x-4)²-16)+9
expand
f(x)=-1(x-4)²+16+9
f(x)=-1(x-4)²+25

vertex form is
f(x)=-1(x-4)²+25

Answer 2

The answer would be y=(x-4)^2+25