Answer:
0.25 mol/L
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 4L
Initial concentration (C1) = 0.5 mol/L
Final volume (V2) = 4 + 4 = 8L
Final concentration (C2) =?
Applying the dilution formula, we can easily find the concentration of the diluted solution as follow:
C1V1 = C2V2
0.5 x 4 = C2 x 8
Divide both side by 8
C2 = (0.5 x 4 )/ 8
C2 = 0.25 mol/L
Therefore the concentration of the diluted solution is 0.25 mol/L
Answer:
4,38%
small molecular volumes
Decrease
Explanation:
The percent difference between the ideal and real gas is:
(47,8atm - 45,7 atm) / 47,8 atm × 100 = 4,39% ≈ <em>4,38%</em>
This difference is considered significant, and is best explained because argon atoms have relatively <em>small molecular volumes. </em>That produce an increasing in intermolecular forces deviating the system of ideal gas behavior.
Therefore, an increasing in volume will produce an ideal gas behavior. Thus:
If the volume of the container were increased to 2.00 L, you would expect the percent difference between the ideal and real gas to <em>decrease</em>
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I hope it helps!
Answer:
A strong alkali is 100% ionised.eg÷sodium hydroxide.
A week alkali is not 100% ionised.eg÷ammonia
A concentrated acid contains a large amount of acid in a given volume.
Answer:
<h2>1000 mL</h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
![P_1V_1 = P_2V_2](https://tex.z-dn.net/?f=P_1V_1%20%3D%20P_2V_2)
Since we're finding the new volume
![V_2 = \frac{P_1V_1}{P_2} \\](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7BP_1V_1%7D%7BP_2%7D%20%20%5C%5C)
We have
![V_2 = \frac{250 \times 4}{1} = 1000 \\](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7B250%20%5Ctimes%204%7D%7B1%7D%20%20%3D%201000%20%5C%5C%20)
We have the final answer as
<h3>1000 mL</h3>
Hope this helps you