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Naya [18.7K]
3 years ago
8

Currently, as Earth's surface becomes warmer, we believe that the level of carbon dioxide in the atmosphere is _____.

Chemistry
2 answers:
Lelechka [254]3 years ago
7 0

Answer:

The answer is A. increasing Hopefully this helps!

tatyana61 [14]3 years ago
6 0

A. Increasing

This is due to the greenhouse effect

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Given that a commercial airliner has a range a range of 9,500 miles using 265 tons of JP-4 fuel. Estimate the range of the aircr
Blizzard [7]

Here is the full question.

Given that a commercial airliner has a range of 9,500 miles using 265 tonnes of JP-4 fuel. Estimate the range of the aircraft burning either gaseous or liquid hydrogen at the same mass of hydrogen as JP4.

The dry mass of the aircraft is 800 tonnes. The fuel properties are as follows:

Fuel                             Density (kg/m³)              Heating value (kJ/kg)

JP4                                 800.0                            45000

H₂ (gaseous, S.T.P)       0.0824                          120900

H₂ (liquid, 1 atm)             70.8                              120900

Answer:

25,514 mi

Explanation:

Let first calculate the value of initial mass of the aircraft m_1 when burning JP4 fuel by using the expression:

m_1 =m_2 + m_{JP4}

where;

m_2 = 800t

m_{JP4} = 265t

m_1 = 800t+265t

m_1=1065 t

We need to employ the use of the range of the airliner which can be expressed by the formula;

s = \eta__0}(\frac{L}{\delta g})In(\frac{m_1}{m_2})(\frac{Q_R}{g})

where;

\eta__0} = overall efficiency

L = lift

\delta g = drag force

m_1 = initial mass of the vehicle

m_2 = is the final mass of the airliner after the burning of fuel

Q_R = is the heat of the reaction of the fuel burning.

g = gravitational acceleration

Rearranging the above equation; we have:

\eta__0}(\frac{L}{\delta g})   = \frac{ s}{In(\frac{m_1}{m_2})({Q_R})}

\eta__0}(\frac{L}{\delta g})   = \frac{9500 mi}{In(\frac{1065t}{800t})({45000 kJ/kg})}

\eta__0}(\frac{L}{\delta g})   = \frac{0.2111}{In(1.33)}

\eta__0}(\frac{L}{\delta g})   = 0.74 mi.kg/kJ

To estimate the range of the aircraft burning either gaseous or liquid hydrogen at the same mass of hydrogen as JP4; we have:

s = \eta__0}(\frac{L}{\delta g})In(\frac{m_1}{m_2})(\frac{Q_R}{g})

s= (0.74mi.kg/kJ)(120900kJ/kg)In(\frac{1065t}{800t})

s= (89466mi)In(\frac{1065t}{800t})

s = (89466mi)In(1.33)

s = 25,513.82 mi

s ≅ 25,514 mi

Thus, the range of the aircraft when burning either gaseous or liquid hydrogen at the same mass of hydrogen as JP4 is 25,514 mi

6 0
3 years ago
What is the air pressure in central texas<br><br>​
Lelu [443]

Answer:

30.8

Explanation: AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

5 0
3 years ago
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What happens to the entropy in the reaction I^2(s) ►I^2(g)?
swat32

Answer:

D. Entropy increases in the reaction.

Explanation:

Entropy is the degree of randomness in a system. In the reaction given we go from a solid to a gas, therefore there is an increase in the randomness. This means there is an increase in entropy.

6 0
3 years ago
The compound consists of 40% carbon and 6.71% hydrogen. Its mass of 1 liter of steam is 2.4 g. What is the formula of the compou
AveGali [126]

I think it is CH2O.

If i'm wrong srry

7 0
3 years ago
8. How much enthalpy/heat is transferred when 0.5113
Gennadij [26K]
First convert to moles:
0.5113 g / 17 g/mol = 0.0301 mol

Now create a ratio based on the reaction provided to solve for the unknown:

4 NH3 / -905.4 kJ = 0.0301 mol NH3 / x kJ
x = -6.808 kJ
8 0
3 years ago
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