Answer : The radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.
Explanation :
As we are given that the Na⁺ radius is 56.4% of the Cl⁻ radius.
Let us assume that the radius of Cl⁻ be, (x) pm
So, the radius of Na⁺ = 
In the crystal structure of NaCl, 2 Cl⁻ ions present at the corner and 1 Na⁺ ion present at the edge of lattice.
Thus, the edge length is equal to the sum of 2 radius of Cl⁻ ion and 2 radius of Na⁺ ion.
Given:
Distance between Na⁺ nuclei = 566 pm
Thus, the relation will be:
The radius of Cl⁻ ion = (x) pm = 181 pm
The radius of Na⁺ ion = (0.564x) pm = (0.564 × 181) pm =102.084 pm ≈ 102 pm
Thus, the radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.
Answer: 0.25m/s2
Explanation:
Acceleration is change in velocity with time
V = final velocity = 5m/s
U =Initial velocity = 3m/s
t = time = 8s
a = Acceleration =?
a = V — U / t
a = (5 — 3) / 8
a = 2/8
a = 0.25m/s2
Answer:
The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons
Explanation:
It is possible to answer this question using Boyle's law:
Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:
160atm×12L = 1atm×V₂
V₂ = 1920L
As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:
1920L - 12L = 1908L
1908L will fill:
1908L×
= <em>636 balloons</em>
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I hope it helps!
Answer:
Volume of liquid = 28.7 mL
Explanation:
Given data;
Density of solid = 3.57 g/ml
Mass of solid = 19.5 g
Volume of water = 23.2 mL
Total volume when solid is dropped into graduated cylinder= ?
Solution:
Density = mass/ volume
v = m/d
v = 19.5 g/ 3.57 g/ml
v = 5.5 mL
Volume of liquid = volume of water + volume of solid
Volume of liquid = 23.2 mL + 5.5 mL
Volume of liquid = 28.7 mL
