When carbon is burned in air carbon iv oxide gas is formed.
C (s) + O2 (g) = CO2(g) ΔH = - 393.5 kj/mol
The enthalpy change of the reaction is -393.5 j/mol which means that when one mole of carbon is completely burnt in air then 393.5 j of energy is evolved.
Thus, 1 mole = -393.5 j , then for 480 kj
= 480 × 1/393.5
= 1.2198 moles
1 mole of carbon iv oxide is equal to 44 g
thus, 1.2198 moles will be 1.2198 × 44 = 53.6712 g of CO2
<h3>Take the weighted average of the individual isotopes.</h3><h3 /><h3>Explanation:</h3><h3>63</h3><h3>C</h3><h3>u</h3><h3> has </h3><h3>69.2</h3><h3>%</h3><h3> abundance.</h3><h3 /><h3>65</h3><h3>C</h3><h3>u</h3><h3> has </h3><h3>30.8</h3><h3>%</h3><h3> abundance.</h3><h3 /><h3>So, the weighted average is </h3><h3>62.93</h3><h3>×</h3><h3>69.2</h3><h3>%</h3><h3> </h3><h3>+</h3><h3> </h3><h3>64.93</h3><h3>×</h3><h3>30.8</h3><h3>%</h3><h3> </h3><h3>=</h3><h3> </h3><h3>63.55</h3><h3> </h3><h3>amu</h3><h3> .</h3><h3 /><h3>If we look at the Periodic Table, copper metal (a mixture of isotopes but </h3><h3>63</h3><h3>C</h3><h3>u</h3><h3> and </h3><h3>65</h3><h3>C</h3><h3>u</h3><h3> predominate) has an approximate atomic mass of </h3><h3>63.55</h3><h3> </h3><h3>g</h3><h3>⋅</h3><h3>m</h3><h3>o</h3><h3>l</h3><h3>−</h3><h3>1</h3><h3> , so we know we are right.</h3>
Answer:
48.75 g of AgCl
11.60 g of H₂S
Solution:
The Balance Chemical Equation is as follow,
Ag₂S + HCl → AgCl + H₂S
<u>Calculate amount of AgCl produced</u><u>,</u>
According to equation,
247.8 g (1 mol) of Ag₂S produces = 143.32 g (1 mol) of AgCl
So,
84.3 g of Ag₂S will produce = X g of AgCl
Solving for X,
X = (84.3 g × 143.32 g) ÷ 247.8 g
X = 48.75 g of AgCl
<u>Calculate amount of H</u><u>₂</u><u>S produced</u><u>,</u>
According to equation,
247.8 g (1 mol) of Ag₂S produces = 34.1 g (1 mol) of H₂S
So,
84.3 g of Ag₂S will produce = X g of H₂S
Solving for X,
X = (84.3 g × 34.1 g) ÷ 247.8 g
X = 11.60 g of H₂S
The conclusion that was drawn from the results of the
gold foil experiment is that electrons in an atom are located in specific
shells. The answer is number 4. Also, he concluded that an atom was not an
empty space but rather, the electrons are scattered.
Protons = Atomic number
Protons + Neutrons = Mass Number
Protons = 20
Neutrons = Atomic number - Mass number
Neutrons = 82 - 20 = 62
