I believe it can be warm because usually the surface below us is warm itself, causing the air to be warm as well. The temperature can vary as well
Answer:
ΔH = 2.68kJ/mol
Explanation:
The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:
q = m*S*ΔT
<em>Where q is heat of reaction in J,</em>
<em>m is the mass of the solution in g,</em>
<em>S is specific heat of the solution = 4.184J/g°C</em>
<em>ΔT is change in temperature = 11.21°C</em>
The mass of the solution is obtained from the volume and the density as follows:
150.0mL * (1.20g/mL) = 180.0g
Replacing:
q = 180.0g*4.184J/g°C*11.21°C
q = 8442J
q = 8.44kJ when 3.15 moles of the solid react.
The ΔH of the reaction is:
8.44kJ/3.15 mol
= 2.68kJ/mol
Answer:
Explanation:
Subscripts are numbers written after elements, subscripts indicate how many of each atom there are in a compound.
It means that 22.5×10^5 J of heat is required to change 1 kg of water into steam.
Latent heat of vaporization is amount of energy required to change 1 gram (in this example 1 kilogram) of material from the liquid to the gaseous state at its boiling point.
Boiling point of the water is 100°C.
Joule (J) is the standard unit for energy (in this example heat).
Evaporization is phase change process in which the water changes from a liquid to a gas (water vapor). Fore example, solar radiation can be the source of energy for evaporation.
More about heat of vaporization: brainly.com/question/14679329
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Answer:
1. C4H8 + 6O2 -----> 4CO2 + 4H20
2. 3836.77 kcal
Explanation:
1. Balanced equation for the complete combustion of cyclobutane:
C4H8 + 6O2 -----> 4CO2 + 4H20
2. Heat of combustion of cyclobutane = 650.3 kcal/mol
Molecular weight of cyclobutane, C4H8 = 56.1 g/mol
Mole of C4H8 : mass of cyclobutane/Molecular weight of cyclobutane
Mole of C4H8 = 331/56.1 = 5.9 mol
Energy released during combustion = 5.9 mol × 650.3 kcal/mol = 3836.77kcal
Therefore the energythat is released during the complete combustion of 331 grams of cyclobutane is 3836.77kcal
