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Lyrx [107]
3 years ago
12

What is the answer -2p-14=p-4(3+p)

Mathematics
2 answers:
saveliy_v [14]3 years ago
8 0
Aaaahahahahahahahahaha
inessss [21]3 years ago
5 0
Order of operations = PEMDAS
parentheses
exponents
multiplication and division
addition and subtraction
-2p-14=p-4(3+p) distribute parentheses
-2p-14=p-12-4p combine like terms
-2p-14=-3p-12 commutative addition
-2p-14+12=-3p commutative again
-2=-3p+2p
-2=-p
p=2
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The sum, S, of the first n even integers can be found using the equation S=n(n+1). If the sum of the first n even integers is 24
Nookie1986 [14]

Answer:

S=n(n+1) therefore 240=n(n+1), 240=2n +n therefore i have to move all to one place and equate to Zero so that will become quadratic equation 240-2n -n=0 so -n -2n +240=0

5 0
2 years ago
I need help with this problem its 620÷20 and 600÷100
dusya [7]
620/20=31

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Those are my answers. :)

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3 years ago
Read 2 more answers
Write the equation of the line that has an undefined slope and passes through the point (3,5)
Arlecino [84]

Undefined slope is when a line becomes vertical. Vertical lines have undefined slope because if we attempt to find the slope using formula, the denominator will become 0 which is undefined.

Next, the equation of a vertical line is x = a where a is any real numbers.

Since the line is vertical, for any a-value would have same y-value which is all real numbers.

However since the graph passes through x = 3. For x = 3 has y-value as set of all real numbers.

Answer

  • The equation for a line that has undefined slope and passes through (3,5) is x = 3

Let me know if you have any doubts!

4 0
3 years ago
How do you graph the quadratic function 8(x-6)^2
babymother [125]
8 translation: narrow or compress graph by a scale factor of 8
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8 0
3 years ago
2sinx / cos3x = tan3x - tanx -verify the identity-
scoundrel [369]

Answer:

cos3x+tan3x=0  

⟹cos3x=−tan3x

⟹cos3x=−sin3xcos3x

⟹cos23x=−sin3x

⟹1−sin23x=−sin3x

⟹sin23x−sin3x−1=0

This is a quadratic equation in sin3x.

sin3x=−(−1)±(−1)2−4×1×(−1)−−−−−−−−−−−−−−−−−√2×1

sin3x=1±5–√2

If x takes real values, the upper sign must be rejected.

sin3x=1−5–√2

⟹3x=nπ+(−1)nsin−11−5–√2

⟹x=13[nπ+(−1)nsin−11−5–√2]

Step-by-step explanation:

Hope this kind of helps

6 0
2 years ago
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