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3 years ago

9

60 is 40 percent of what number

1 answer:

nydimaria [60]3 years ago

6 0

240 plz like my awnser it would mean alot

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Select the correct answer.

Irina18 [472]

D. About 122 units I just took the test

4 0

2 years ago

*Translate into an algebraic expression: How much 50% sugar syrup can you make if you have x grams of sugar?

Irina-Kira [14]

Answer:

w = x/50% = x/50/100

Step-by-step explanation:

We would turn the above question into an algebraic expression using variables.

To make a sugar syrup, we need sugar and water to form the solution.

Amount of sugar = x gram

Let amount of water = w gram

Sugar syrup solution = 50%

Sugar syrup solution = (amount of sugar)/(amount of water) × 100

50% = x/w × 100%

50% = x/w

Making w subject formula

w = x/50%

w = x/50/100

5 0

3 years ago

Please help :) I have no clue & math isn’t my strong subject.

melisa1 [442]

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

Solution:

Given line $y=\frac{4}{7} x+4$ .

Slope of this line, $m_1$ = $\frac{4}{7}$

$$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }$

$$m_2=\frac{-1}{m_1}$

$$=\frac{-1}{\frac{4}{7} }$

Slope of perpendicular line, $m_2=\frac{-7}{4}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$y-y_1=m(x-x_1)$

$$y-(-7)=\frac{-7}{4} (x-5)$

$$y+7=\frac{-7}{4} x+\frac{35}{4}$

Subtract 7 from both sides, we get

$$y=\frac{-7}{4} x+\frac{7}{4}$

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

To find the parallel line:

Slopes of parallel lines are equal.

$m_1=m_3$

$$m_3=\frac{4}{7}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$$y-(-7)=\frac{4}{7} (x-5)$

$$y+7=\frac{4}{7} x-\frac{20}{7}$

Subtract 7 from both sides,

$$y=\frac{4}{7} x-\frac{69}{7}$

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

7 0

3 years ago

Which quadratic equation equation is equivalent to (x^2-1)^2 -11(^2-1) +24=0

cluponka [151]

$(x^2-1)^2-11(x^2-1)+24=0$

Use substitution: $x^2-1=t$

$t^2-11t+24=0\\\\t^2-8t-3t+24=0\\\\t(t-8)-3(t-8)=0\\\\(t-8)(t-3)=0\iff t-8=0\ \vee\ t-3=0\\\\t=8\ \vee\ t=3$

<span>we're going back to substitution:

$x^2-1=8\ \vee\ x^2-1=3\ \ \ \ |add\ 1\ to\ both\ sides\ of\ the\ equations\\\\x^2=9\ \vee\ x^2=4$

therefore

$x=\pm\sqrt9\ \vee\ x=\pm\sqrt4\\\\\boxed{x=-3\ \vee\ x=3\ \vee\ x=-2\ \vee\ x=2}$
</span>

6 0

3 years ago

Read 2 more answers

What’s the answers that go in each box, write them in the form (x,y).

IceJOKER [234]

the pic is really blurry i cant see anything.

5 0

3 years ago