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Alex Ar [27]
3 years ago
13

Mariel and Liu are running a long-distance race. Mariel runs at a rate of 5.4 m/s, and Liu runs at a rate of 7.6 m/s. If Mariel

has a 20 m head start, how long will it take for Liu to catch Mariel?
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0

We have that, how long it will take for Liu to catch Mariel is mathematically given as

t=3.076s

From the question we are told

Mariel and Liu are running a long-distance race. Mariel runs at a rate of 5.4 m/s, and Liu runs at a rate of 7.6 m/s. If Mariel has a 20 m head start, how long will it take for Liu to catch Mariel?

Generally the equation for the Average speed is  mathematically given as

v_a=\frac{5.4+7.6}{2}\\\\V_a=6.5m/s

Therefore

How long it will take for Liu to catch Mariel is mathematically given as

t=\frac{20}{6.5}

t=3.076s

For more information on this visit

brainly.com/question/23379286

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Which list is in order from least to greatest? 1.94 times 10 Superscript negative 5, 1.25 times 10 Superscript negative 2, 6 tim
sergij07 [2.7K]

Answer:

The options in the question was not properly arranged/ formatted. See the arranged options in the explanation section

The correct option is A.

1.94 times 10 Superscript negative 5, (1.9 x 10⁻⁵)

1.25 times 10 Superscript negative 2 (1.25 x 10⁻²),  

6 times 10 Superscript 4 (6 x 10⁴),  

8.1 times 10 Superscript 4  (8.1 x 10⁴)

Step-by-step explanation:

Which list is in order from least to greatest?

1.94 times 10 Superscript negative 5,

1.25 times 10 Superscript negative 2,

6 times 10 Superscript 4,

8.1 times 10 Superscript 4

1.25 times 10 Superscript negative 2,

1.94 times 10 Superscript negative 5,

6 times 10 Superscript 4,

8.1 times 10 Superscript 4

1.25 times 10 Superscript negative 2,

1.94 times 10 Superscript negative 5,

8.1 times 10 Superscript 4,

6 times 10 Superscript 4

1.94 times 10 Superscript negative 5,

1.25 times 10 Superscript negative 2,

8.1 times 10 Superscript 4,

6 times 10 Superscript 4

Which list is in order from least to greatest?  

A.

1.94 times 10 Superscript negative 5, (1.9 x 10⁻⁵)

1.25 times 10 Superscript negative 2 (1.25 x 10⁻²),  

6 times 10 Superscript 4 (6 x 10⁴),  

8.1 times 10 Superscript 4  (8.1 x 10⁴)

B

1.25 times 10 Superscript negative 2 (1.25 x 10⁻²),  

1.94 times 10 Superscript negative 5 (1.9 x 10⁻⁵),  

6 times 10 Superscript 4 (6 x 10⁴),  

8.1 times 10 Superscript 4  (8.1 x 10⁴)

C.

1.25 times 10 Superscript negative 2 (1.25 x 10⁻²),

1.94 times 10 Superscript negative 5 (1.9 x 10⁻⁵),  

8.1 times 10 Superscript 4 (8.1 x 10⁴),  

6 times 10 Superscript 4  (6 x 10⁴)

D.

1.94 times 10 Superscript negative 5 (1.9 x 10⁻⁵),  

1.25 times 10 Superscript negative 2 (1.25 x 10⁻²),

8.1 times 10 Superscript 4 (8.1 x 10⁴),

6 times 10 Superscript 4  (6 x 10⁴)

5 0
3 years ago
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7 0
3 years ago
a ladder 13m long is placed on the ground in such a way that it touches the top of a vertical wall 12m high. find the distance o
Sergio039 [100]

Answer:

by applying Pythagoras theorem;

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the wall (12m) acts as height

the distance between the the two is the base

therefore

a² + b² = c²

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8 0
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sasho [114]
.75. Hope this helps :D
6 0
3 years ago
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What could the answer be?
VashaNatasha [74]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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