Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.
If you would to solve 60% of 85 is what number, you can calculate this using the following steps:
60% of 85 is x
60% * 85 = x
x = 60% * 85 = 60/100 * 85 = 51
Result: 60% of 85 is 51.
<u>Corrected Question</u>
The Venn diagram shows three types of numbers: odd (O), even (E), and prime (P). Which is represented by Ø?
(A) O ⋃ P (B)E ∩ P (C)O ⋃ E (D)E ∩ O
Answer:
(D) E ∩ O
Step-by-step explanation:
The Venn diagram is reproduced and attached below.
In the Venn diagram, the sets of Odd(O) and Even(E) numbers are disjoint, i.e. there is no intersection.
We can also say the intersection of sets O and E is the empty set.
Therefore: E ∩ O is represented by the empty set Ø.
Generally speaking, a number cannot be even and odd at the same time.
The correct option is D
<span>A board is 5 inches long. The division sentence shows that when the board is cut into inch pieces, each piece will be will be inches long.
</span>hopes this helps :) :D :)
Answer:
<em>The SUV is running at 70 km/h</em>
Step-by-step explanation:
<u>Speed As Rate Of Change
</u>
The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.
This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)
We'll compute :


We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

Thus we have

Solving for x'

Since y'=-60


The SUV is running at 70 km/h