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2 years ago

When completing the square, does the value of A always need to be one? Thanks

Mathematics

1 answer:

Greeley [361]2 years ago

4 0

Yeah, mostly is has to be negative, but in some cases a is greater than 1 than we do some other operations.

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I'LL MARK BRAINLIEST JUST PLEASE HELP!!!!! A bag is filled with different color balls. Craig selects a ball at random, records t

MatroZZZ [7]

The relative frequency of choosing yellow ball is: 0.25

good luck

7 0

3 years ago

Which letters label the locations of the opposite numbers - 1 and 1?

andreev551 [17]

Answer:

Step-by-step explanation:

C and D are the location for -1 and 1

....-2 -1 0 1 2 ...

3 0

3 years ago

the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai

Blababa [14]

Let $X$ be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

$P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10$

where $Z$ follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

$P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)$

where $F_Z(z)=P(Z\le z)$ denotes the CDF of $Z$ , and $F_Z^{-1}$ denotes the inverse CDF. We have

$z_1=F_Z^{-1}(0.90)\approx1.2816$

Similarly, because 20% of students obtain less than 40 marks, we have

$P(X$

so that

$P(Z$

Then $\mu,\sigma$ are such that

$\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma$

$\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma$

and we find

$\mu\approx53.8739,\sigma\approx16.4848$

3 0

3 years ago

Please help and explain if you can

finlep [7]

You're pretty much screwed

4 0

3 years ago

Simplify ^3_/125x^21y^33

Grace [21]

$\sqrt[3]{125x^{21}y^{33}}=\sqrt[3]{125}\cdot\sqrt[3]{x^{21}}\cdot\sqrt[3]{y^{33}}=\sqrt[3]{5^3}\cdot\sqrt[3]{(x^7)^3}\cdot\sqrt[3]{(y^{11})^3}\\\\=\boxed{5x^7y^{11}}\\\\Used:\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt[n]{a^n}=a\\\\(a^n)^m=a^{nm}$

7 0

3 years ago