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Dafna1 [17]
3 years ago
14

When completing the square, does the value of A always need to be one? Thanks

Mathematics
1 answer:
Greeley [361]3 years ago
4 0

Yeah, mostly is has to be negative, but in some cases a is greater than 1 than we do some other operations.

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PLS HELP ME WITH MATH!!!!!​
Romashka-Z-Leto [24]

Answer:

<u>⚪</u><u> </u><u>(</u><u>4</u><u> </u><u>•</u><u> </u><u>3</u><u>)</u><u> </u><u>+</u><u> </u><u>(</u><u>4</u><u> </u><u>•</u><u> </u><u>8</u><u>)</u>

Step-by-step explanation:

4•(3 + 8)

by distributing 4 in the bracket:

=  \{(4•3) + (4•8) \}

6 0
3 years ago
One side if the labtop is 9.5 inches and the other side is 14 inches. Using the Pythagorean Theron, what is the length of the di
Digiron [165]

(side 1)² + (side 2)² = (diagonal)²

(9.5² + (14)² = (diagonal)²

90.25 + 196 = (diagonal)²

286.25 = (diagonal)²

√286.25 = √(diagonal)²

17 = diagonal

Answer: 17 inches

3 0
3 years ago
Find the solution of the system of equations<br> shown on the graph.
o-na [289]

Answer:

Answer:(0,3)Step-by-step explanation:The solution in a set of graphs is where they intersect. In this graph, they intersect at (0,3)

4 0
2 years ago
g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o
natali 33 [55]

Answer:

The tangent line to the given curve at the given point is y=9x-26.

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of y=2x^2-7x+6 and then evaluate it for x=4.

(y=2x^2-7x+6)'          Differentiate the equation.

(y)'=(2x^2-7x+6)'       Differentiate both sides.

y'=(2x^2)'-(7x)'+(6)'    Sum/Difference rule applied: (f(x)\pmg(x))'=f'(x)\pm g'(x)

y'=2(x^2)'-7(x)'+(6)'  Constant multiple rule applied: (cf)'=c(f)'

y'2(2x)-7(1)+(6)'        Applied power rule: (x^n)'=nx^{n-1}

y'=4x-7+0               Simplifying and apply constant rule: (c)'=0

y'=4x-7                    Simplify.

Evaluate y' for x=4:

y'=4(4)-7

y'=16-7

y'=9 is the slope of the tangent line.

Point slope form of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on the line.

Insert 9 for m and (4,10) for (x_1,y_1):

y-10=9(x-4)

The intended form is y=mx+b which means we are going need to distribute and solve for y.

Distribute:

y-10=9x-36

Add 10 on both sides:

y=9x-26

The tangent line to the given curve at the given point is y=9x-26.

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function f(x)=2x^2-7x+6 at x=4 (the slope of the tangent line at x=4):

\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}

\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}  We are given f(4)=10.

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

2x^2-7x-4=(x-4)(2x+1)

Let's check this with FOIL:

First: x(2x)=2x^2

Outer: x(1)=x

Inner: (-4)(2x)=-8x

Last: -4(1)=-4

---------------------------------Add!

2x^2-7x-4

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}

\lim_{x \rightarrow 4}(2x+1)

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0
3 years ago
Which graph is correct for the given equation: Y=-1/4x-4?
navik [9.2K]

Answer:

c

Step-by-step explanation:

i believe it's hard to see the graph

3 0
3 years ago
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