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3 years ago

What percent of 120 is 78?

2 answers:

6 0

65% since 78/120 is .78 and when moving from decimal to percent you move the decimal place two times to the right
hope this helps

frosja888 [35]3 years ago

5 0

78/120 = 0.65

0.65 = 65%

Hope this helped☺☺

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If the value of x=4, y=3 and z= -2 find the value of 2x+3z

Oksana_A [137]

Answer:

Step-by-step explanation:

To find value:

2x + 3z

Given values:

x = 4, y = 3 and z = -2

Solution:

2x + 3z

(Putting the values of x = 4 and z = -2)

= 2(4) + 3(-2)

= 8 - 6

= 2 (Ans)

8 0

3 years ago

Read 2 more answers

1 point

-Dominant- [34]

39
Divide 78 by 2 to get 39 and add in to the number

5 0

3 years ago

What is the equation of a line that is parallel to −x+3y=6 and passes through the point (3, 5) ?

oksian1 [2.3K]

3y=6+x
y=(6+x)/3
y=2+x/3
y=mx+b
y=x/3+b
so m(slope) is 1/3
use the point (3, 5), sub this for x and y
5=3/3+b
5-1=b
b=4
therefore, y=x/3+4
or y=(1/3)x+4 (you can write it like this as well)

5 0

3 years ago

Solve for h. h − 999 = –341

scZoUnD [109]

I think h is 658 i could be wrong

8 0

3 years ago

Read 2 more answers

I need some help with math

Irina18 [472]

Answer:

$(y-7)^2+(x-2)^2=16$

and

$(x+2)^2+(y-15)^2 = 9$

Step-by-step explanation:

The standard equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where the coordinate (h,k) is the center of the circle.

Second Problem:

We can start with the second problem which uses this info very easily.
(h,k) in this problem is (-2,15) simply plug these into the equation. $(x--2)^2+(y-15)^2=r^2$ .
We can also add the radius 3 and square it so it becomes 9. The equation.
This simplifies to $(x+2)^2+(y-15)^2 = 9$ .

First Problem:

The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
$y^2-14y+x^2-4x+37=0$ first subtract 37 from both sides so the equation is now $y^2-14y+x^2-4x=-37$ .
$y^2-14y+x^2-4x+37=0$ by adding $(-\frac{b}{2a} )^2$ to both the x and y portions of this equation you can complete the squares. $(-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2$ and $(-\frac{-4}{2(1)})^2$ which equals 49 and 4.
Add 49 and 4 to both sides and the equation is now: $y^2-14y+49+x^2-4x+4=-37+49+4$ You can simplify the y and x portions of the equations into the perfect squares or factored form $(y-7)^2$ and $(x-2)^2$ .
Finally put the whole thing together. $(y-7)^2+(x-2)^2=16$ .

I hope this helps!

5 0

3 years ago