Since the standard form of the circle is:
(x-h)^2+(y-k)^2=r^2, and (h,k)=(0,0) and r=10 so we have:
x^2+y^2=100 Looking at the points you have:
(√10, 0) does not work as (√10)^2+0^2=10+0=10
(0, 2√5) does not work as 0^2+(2√5)^2=0+20=20
(5√2, 5√2) works as (5√2)^2+(5√2)^2=50+50=100
Step-by-step explanation:
Circumference of Circle =

given d = 19.4mi
r = 1/2d
= 1/2 x 19.4
= 9.7mi
Circumference of Circle =

(8+2x) -> If 8 is added to twice a number (x)
5*(8+2x) -> and this sum is multiplied by 5
5*(8+2x)=x*(-28)+2 -><span>the result is the same as if the number is multiplied by negative −28 and 2 is added to the product.
Simplifying the equations on both sides would give
40+10x=-28x+2 transpose -28 to the left side and 40 to the right side
28x+10x=2-40
38x=-38
x=-1</span>
Answer:
Apply the binomial expansion...