<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,

0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
Answer:
28/32 and 26/32
Step-by-step explanation:
A common denominator of 8 and 16 is 32.
7/8 = (7 * 4)/(8 * 4) = 28/32
13/16 = (13 * 2)/(16 * 2) = 26/32
Two equivalent fractions with a common denominator are 28/32 and 26/32.
Answer:
n = 144
Step-by-step explanation:
6 / n = 5/120
6 * 120 = 5*n
5n = 6*120
5n = 720
n = 720/5
n = 144
Answer:
0,7
Step-by-step explanation:
16 over 3 is the answer u write the numerator above the denominator 6 over 1 minus 2 over 3 6 times 3 over 1 x3 minus 2 over 3 u get 18 minus 2 over 3 and subtract 18 and 2 u get 16 over 3