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3 years ago

6

Simplify these two problems and show how you got them.

1 answer:

bogdanovich [222]3 years ago

5 0

Step-by-step explanation:

all work is shown and picture

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Ira bought a tennis racquet that cost $112. The sales tax rate is 9 percent. What is the total amount that she paid?

zvonat [6]

Wouldnt 9% bc 9 cents ?

5 0

2 years ago

NemiM [27]

Answer:

D. 2 3 • 3 2 • 5

Step-by-step explanation:

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8 0

3 years ago

This is a picture of a cube and the net for the cube.<br><br> What is the surface area of the cube?

mina [271]

Answer:

$486\ in^2$

Step-by-step explanation:

we know that

The surface area of the cube is equal to the area of its six square faces

so

$SA=6b^2$

where

b is the length side of the cube

we have

$b=9\ in$

substitute

$SA=6(9)^2=486\ in^2$

4 0

3 years ago

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the re

alukav5142 [94]

Answer:

Step-by-step explanation:

$\text{Given that:}$

$y = 1+ sec(x) \ \ y =3$

$\text{we draw the graph and the curves intersect at:}$

$x = - \dfrac{\pi}{3} \ and \ x = \dfrac{\pi}{3}$

$\text{Applying washer method;}$

$f(x) _{outer} - g(x) _{inner} --- (1)$

$V= \int ^b_a A(x) \ dx --- (2)$

$\text{outer radius = 3 - 1 = 2}$

$\text{inner radius =}$ $( 1 + sec(x) ) - 1 = sec (x)$

$A(x) = \pi ((2)^2 -(sec(x)^2) \\ \\ A(x) = \pi (4 - sec^2 (x)) ---- (3)$

$\text{The volume V =}\int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ A(x) \ dx$

$V = \int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ \pi (4- sec^2 (x) ) \ dx$

$V = 2 \pi \int ^{\dfrac{\pi}{3}}_{0}( 4 - sec^2 (x)) \ dx$

$V = 2 \pi \int ^{\pi/3}_{0} 4 . \ dx - 2 \pi \int ^{\pi/3}_{0} sec^2 (x) \ dx$

$V = 2 \pi(4) \int ^{\pi/3}_{0} 1 . \ dx - 2 \pi \Big( tan (x)\Big )^{\dfrac{\pi}{3}}_{0}$

$V = 8 \pi(x)^{\dfrac{\pi}{3}}_{0} - 2 \pi \Big( tan \dfrac{\pi}{3} -tan (0)\Big )$

$V = 8 \pi({\dfrac{\pi}{3}}-{0}) - 2 \pi \Big( tan \sqrt{3}-(0)\Big )$

$V = 8 \pi({\dfrac{\pi}{3}}) - 2 \pi \Big( \sqrt{3}\Big )$

$\mathbf{V = 2 \pi \Big(\dfrac{4\pi}{3}- \sqrt{3} \Big)}$

8 0

2 years ago

Guys pls help me!!!!!!!!

DENIUS [597]

Answer:

D. y = -x^2 + 1

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers