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cupoosta [38]
4 years ago
11

As shown in the figure below, a squirrel is looking for nuts. it runs rightward 10m and runs leftwards another 20m to a second n

ut. The total time spent running was 12s. What is the squirrels average velocity to reach the second nut?
Physics
2 answers:
Nata [24]4 years ago
7 0

Answer:

Velocity: -0.83

Average speed: 2.5

White raven [17]4 years ago
6 0

Answer:

Average velocity = 0.83 m/s

Explanation:

Computation:

Total displacement = 20 - 10 = 10 m

Time taken = 12 second

Average velocity = Total displacement / Time taken

Average velocity = 10 /12

Average velocity = 0.83 m/s

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A very long train is rolling at 4 m/s along a straight track. An observer is standing on the ground very dangerously close to th
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Answer:

A. \vec{r}=(6\frac{m}{s})t\ \ \hat{i}

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Explanation:

A. The vectorial equation of the person who is getting closer to the other person is:

\vec{r}=\vec{v}t

r: position vector

v: speed vector = 6m/s i  (if you consider the motion as a horizontal motion)

Then, you replace and obtain:

\vec{r}=(6\frac{m}{s})t\ \ \hat{i}

B. The time is:

t=\frac{d}{v}

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3 years ago
On a popular amusement park ride, the riders stand along the inside wall of a large cylinder with a diameter of 8.27 m. The cyli
____ [38]

Answer:

Explanation:

D = 8.27 m   ⇒  R = D / 2 = 8.27 m / 2 = 4.135 m

ω = 0.66 rev/sec = (0.66 rev/sec)*(2π rad/1 rev) = 4.1469 rad/s

We can apply the equation

Ff = W  ⇒  μ*N = m*g   <em>(I)</em>

then we have

N = Fc = m*ac = m*(ω²*R)

Returning to the equation <em>I</em>

<em />

μ*N = m*g    ⇒    μ*m*ω²*R = m*g   ⇒ μ = g / (ω²*R)

Finally

μ = (9.81 m/s²) / ((4.1469 rad/s)²*4.135 m) = 0.1379

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