Answer: I added a picture of the answer
Explanation: its right
Electric field strength decreases as the distance from the source increases.
<h3>
How the distance from the charge affects the magnitude of the electric field?</h3>
The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.
So we can conclude that Electric field strength decreases as the distance from the source increases.
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25,000 Feet = 7620m
PE = mgh where m is mass, g is gravity accel: 9.8 n h is height
= 90 x 9.8 x 7620
= 6720840J
= 6.72MJ
F = ma where m is mass, a is accel = gravity = 9.8
= 90 x 9.8
= 882N
Accel = gravity = 9.8m/s^2
KE = 1/2mv^2 where m is mass n v is vel
if no wind resistance, PE leaving airplane = KE at net
6720840 = 1/2 x 90 x v^2
v^2 = 149352
v = 386.5m/s
Answer:
Explanation:
Check attachment for solution
Answer:
t15 kg
Explanation:
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