Assuming constant acceleration <em>a</em>, the object has undergoes an acceleration of
<em>a</em> = (50 m/s - 100 m/s) / (25 s) = -2 m/s²
Then the net force has a magnitude <em>F</em> such that, by Newton's second law,
<em>F</em> = (75.0 kg) <em>a</em>
<em>F</em> = (75.0 kg) (-2 m/s²)
<em>F</em> = -150 N
meaning the object is acted upon by a net force of 150 N in the direction opposite the initial direction in which the object is moving.
Answer:
2025000 J
Explanation:
The formula for kinetic energy is KE=.5(m)(v²).
The initial kinetic energy is 0 because it is at rest. .5(m)(0) = 0.
To calculate the final kinetic energy, use the kinetic energy equation. KE = .5(2000)(45²) = 2025000 J.
To find the change in kinetic energy, you do KE(f) - KE(i). 2025000-0 = 2025000 J.
The structure and curvature of the Earth results in beams of sunlight glancing off the equator and reaching other areas of the Earth. This means that the areas at the equator receive more energy as sun's rays hit them directly.
Therefore, the answer is C.
Answer: 3kg: 14.7 6kg: 29.4 9kg: 44.1
Explanation: just did it on Edge
Answer:
2. much hotter and much denser than its surface
Explanation:
We know that the temperature around the center of the Sun is about 1.57×10⁷ K and its density is about 162 g/cm³.
Now, the temperature and the density decrease as one moves outward from the center of the Sun, the temperature at the surface of the sun is about 5×10³ K and the density as an average in the surface is about 1.4 g/cm³.
Therefore the answer is:
2. much hotter and much denser than its surface.
I hope it helps you!
Have a nice day!
