terms = ["Bandwidth", "Hierarchy", "IPv6", "Software", "Firewall", "Cybersecurity", "Lists", "Program", "Logic",
"Reliability"]
def swap(arr, in1, in2):
w = arr[in1]
arr[in1] = arr[in2]
arr[in2] = w
print(terms)
swap(terms, 5, 1)
swap(terms, 2, 4)
swap(terms, 3, 5)
swap(terms, 5, 6)
swap(terms, 6, 8)
swap(terms, 8, 9)
print(terms)
This is how I interpreted the question. If I need to make any changes, I'll do my best. Hope this helps though.
helps us for typing letters, numbers and symbols etc.
Explanation:
if you have any doubts or queries regarding the answer please feel free to ask
Answer:
I believe "..." means that you need to go further in depth with your writing.
Answer:
The correct answer is:
C. ndx = 0;
while (ndx < 3) {
ar[ndx] = 0;
ndx++;
}
Explanation:
The declaration given is:
int ar[3];
This means the array consists of three locations and is named as ar.
We know that the indexes are used to address the locations of an array and the index starts from 0 and goes upto to 1 less than the size of the array which means the indexes of array of 3 elements will start from 0 and end at 2.
Now in the given options we are using ndx variable to run the while loop.
So the code to assign zero to all elements of array will be
ndx = 0;
while(ndx<3)
{
ar[ndx] = 0;
ndx++;
}
Hence, the correct answer is:
C. ndx = 0;
while (ndx < 3) {
ar[ndx] = 0;
ndx++;
}
