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slava [35]
3 years ago
15

When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and at least o

ne numerator determinant is zero, then the system _____________________.
A. is consistent
B. is dependent
C. is inconsistent
D. has no solution
Mathematics
1 answer:
Ainat [17]3 years ago
7 0

Answer:

  B. is dependent

Step-by-step explanation:

The denominator determinant will be zero when the coefficients of the variables are dependent. One of the numerator coefficients will be zero when the coefficients involved are dependent. Hence using Cramer's Rule will result in the ratio 0/0 when the system is dependent.

___

The ratio will be 1/0 if the system is inconsistent (has no solution).

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Answer:

Y=4x+9

Step-by-step explanation:

Use rise over run to find 2 points for the slope. B is as simple as looking where the line passes y.

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3 years ago
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What’s the length of three pipes, when combined they equal 72m, how do I find the answer
allochka39001 [22]

Answer:

Each pipe is 24m

Step-by-step explanation:

<u>Given:</u>

  • three pipes
  • combined equal 72m
  • let the variable x represent the length of 1 pipe

<u>Algebraic Expression</u>:

3 pipes times length equals 72m (the total length)

3x = 72, we want x to be alone so divided both sides by 3

3x / 3 = 72 / 3

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Learn more about Algebraic Expression here: brainly.com/question/4344214

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2 years ago
he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

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3 years ago
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