100%/x%=60/18
<span>(100/x)*x=(60/18)*x </span>
<span>100=3.33333333333*x </span>(3.33333333333)
<span>100/3.33333333333=x </span>
<span>30=x </span>
x=30
<span>now we have: </span>
<span>18 is 30% of 60</span>
Answer: In 10 hours, 4000 bacteria will be present.
Step-by-step explanation:
Given that 2000 bacteria grew to 2400 in 2 hours,
growth/ increase rate = 2400 - 2000
= 400 bacteria increase in 2 hours
Per hour is therefore 400/2 = 200 bacteria increase per hour
If the bacteria increases by 200 per hour
If 200 = 1 hour
X = 10 hours
We cross multiply:
X = 200 x 10
X = 2000
Therefore, a culture with 2000 bacteria at the same growth rate will have increased by additional 2000 in 10 hours
So, after 10 hours, number of bacteria will be 2000 + 2000 = 4000 bacteria
Method 1.
Look at the picture 1.
We have:
Picture 2.
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Method 2. (Picture 3)
ΔLOM and ΔMON are isosceles triangles. Therefore the two angles opposite the legs are equal.
The sum of the internal angles in each triangle is 180°. Thereofre in ΔLMN we have:
Answer:
The cost for 1 chair is $2.75 and the cost for 1 table is $8.75
Step-by-step explanation:
Use the elimination method of linear equations to find your answer.
Our equations for this problem are:
3c+5t=52 and 9c+7t=86
1. Multiply the entire first equation by -3.
-3(3c+5t=52)
2. Simplify the equation from above:
-9c-15t=-156
3. Stack the two equations on top of each other and add/subtract:
-9c-15t=-156
9c+7t=86
4. You should be left with -8t=-70. Simplify this to find the value of t:
t=8.75
5. Plug the value of t into any of the original equations and solve for c.
3c+5(8.75)=52
6. Simplify the equation above:
3c+43.75=52
7. Subtract 43.75 from both sides of the equation:
3c=8.25
8. Divide both sides by 3 to get your c value:
c=2.75
Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x 
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x 
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
