So, x = 13, x = √3 and x =7i.
now, recall that for an EVEN radical, there are two possible roots, namely is say √3 is say hmmm some value "a", that means that a*a = √3, however, -a*-a is also √3, therefore, ±√3 are two valid values, and therefore -√3 is another one.
now.... keep in mind that, complex solutions or roots, never come all by their lonesome, their sister is always with them, the conjugate, so, for 7i or namely 0 + 7i, her sister is always around, 0 - 7i, which is the other root.
Answer:
4x(2x+3)
Step-by-step explanation:
Since the common factor of 8x^2 and 12x is 4x, put that out and separate the distributed remaining factors.
Step-by-step explanation:
a = 2i + j - k
b = -1 -7j + k
a × b = (2i + j - k) (-1 + 7j + k)
-2i + 14ij + 2ik - j + 7j^2 + jk + k -7jk - k^2
-2i + 14ij + 2ik -j +7j^2 +jk - 7jk + k - k^2
-2i + 14ij + 2ik - j +7j^2 - 6jk + k - k^2
The answer is y = +8
Explanation:
Since they tell us what x equals (3), let's plug that into the equation
y = (3) + 5
Now, we can just add 3 and 5 together, which we get 8
y = +8
Answer:
from June to July
Step-by-step explanation:
the biggest change was $70
