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3 years ago

Write a whole number that rounds to

Mathematics

2 answers:

irina1246 [14]3 years ago

8 0

1999 you can just subtract one and you have your answer

dimaraw [331]3 years ago

6 0

1999

hope this answer helps!!!!

please rate, thank, and mark as brainliest!!!! :D

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2^2 times 2^3 a.2^4 b.2^5 c.2^6 d.4^6

maxonik [38]

Answer:

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5. x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4. 24 can also be written as 4 × 6 and √4 = 2. So x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3. x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3. x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4. 88 can also be written as 4 × 22 and √4 = 2. So x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1. x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4. x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6. x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4. x = 9 ± √33 / 4 .

5 0

3 years ago

Read 2 more answers

PLS ANSWER FAST!! WILL GIVE BRAINLIEST!!

horrorfan [7]

Answer:

500^1/3

Step-by-step explanation:

Since it is a cube root, the exponent is 1/3.

8 0

2 years ago

PLEASE HELP FAST ILL GIVE 5 STARS!!!!

MArishka [77]

I believe it's Line y=-x+2 and y=3x+1 intersect the y-axis. From what I've gathered, they are parallel lines, and both are set on the y-axis.

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3 years ago

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NO LINKS!! Please help me with these notes. Part 1a

erik [133]

Answers:

When we evaluate a logarithm, we are finding the exponent, or power x, that the base b, needs to be raised so that it equals the argument m. The power is also known as the exponent.

$5^2 = 25 \to \log_5(25) = 2$

The value of b must be positive and not equal to 1

The value of m must be positive

If 0 < m < 1, then x < 0

A logarithmic equation is an equation with a variable that includes one or more logarithms.

===============================================

Explanation:

Logarithms, or log for short, basically undo what exponents do.

When going from $5^2 = 25$ to $\log_5(25) = 2$ , we have isolated the exponent.

More generally, we have $b^x = m$ turn into $\log_b(m) = x$

When using the change of base formula, notice how

$\log_b(m) = \frac{\log(m)}{\log(b)}$

If b = 1, then log(b) = log(1) = 0, meaning we have a division by zero error. So this is why $b \ne 1$

We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.

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3 years ago

The value of\[\left( 1-{1\over3} \right)\left( 1-{1\over4} \right)\left( 1-{1\over5} \right)....\left( 1-{1\over n} \right)\]is

Oliga [24]

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3 years ago