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3 years ago

Write a whole number that rounds to

Mathematics

2 answers:

irina1246 [14]3 years ago

8 0

1999 you can just subtract one and you have your answer

dimaraw [331]3 years ago

6 0

1999

hope this answer helps!!!!

please rate, thank, and mark as brainliest!!!! :D

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What is the sum of the arithmetic sequence 151, 137, 123,..if there are 26 terms?

ElenaW [278]

First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)

nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
an = -14n+165

This will be used in the formula below

Sn = n*(a1+an)/2
Sn = n*(151+(-14n+165))/2
S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
S26 = -624

The final answer here is choice C) -624

5 0

3 years ago

joann is having a party. she wants to make punch. the recipe for punch uses 4 pints of orange juice, 5 cups of apple juice, 1/2

Aleks [24]

4 pints= 8 cups
+
1/2 gallon= 8 cups
+
2 quarts= 8 cups
+
5 cups
=29
no, she is off by a cup

7 0

3 years ago

Ayden has a goal of finishing painting at least 80% of the 500 square meters of a houses walls by today. He actually finished pa

svlad2 [7]

Answer:

Ayden has reached his goal. He has painted 83%.

Step-by-step explanation:

80% of 500 square meters is 400 square meters. Ayden has painted 415 square meters which is 83%.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7

Katen [24]

$\green{\large\underline{\sf{Solution-}}}$

Given expression is 

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

Hence, 

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

3 years ago

-8= -2(z+7) How do you sovle this equation

Anna71 [15]

$-8= -2(z+7)$ Equation

$\dfrac{-8}{-2} =z+7

 
$ $Divide \ both \ sides \ by \ -2$

 $\dfrac{8}{2} =z+7$

$4=z+7

 
$

$4-7=z$ $Subtract \ 7 \ from \ both \ sides$

$z=-3$ $Solution$

5 0

3 years ago

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