We have a line tangent to the circle with center B at point C. We know that the angle formed between the tangent line at the point of intersection to the line extended from that point to the center of the circle is equal to 90°. In the problem, the 90° is for ∠BCA. We also know that the summation of all angles in a triangle is 180°. We have the solution below for the ∠BAC
180°=∠BAC + ∠BCA + ∠ABC
180°=∠BAC + 90° + 40°
∠BAC =50°
The answer is 50°.
Hey there Smarty!
This would be considered to be a (acute angel) which in this case, we would have to make sure that this whole triangle would equal less than 270 because each angle would be less than
°
If we add/multiply
.
So, we would have to know that was ever this would all add up to be, this would have to be less than 270°
I truly hope this helps, and also, it's kind of my
first time doing this I hope this would be helpful.
~Jurgen
Answer:
it's C.
Step-by-step explanation:
Im pretty sure x y should be 30, I hope this helps.
7.5. 30 divided by 4 equals 7.5