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2 years ago

Find the profit or loss if:

Mathematics

2 answers:

photoshop1234 [79]2 years ago

8 0

Answer:

It would be a profit of .35 cents

Step-by-step explanation:

rewona [7]2 years ago

8 0

Answer:

it is a profit by 0.35 cents

Step-by-step explanation:

That is becuase it costed you 19.85 so you ost 19.85 and gain 35 cents becuase you are selling it for a higher price

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Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.

sp2606 [1]

Answer:

(A) The odds that the taxpayer will be audited is approximately 0.015.

(B) The odds against these taxpayer being audited is approximately 65.67.

Step-by-step explanation:

The complete question is:

Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.

A. What are the odds that the taxpayer will be audited?

B. What are the odds against such tax payer being audited?

Solution:

The proportion of U.S. taxpayers who were audited is:

P (A) = 0.015

Then the proportion of U.S. taxpayers who were not audited will be:

P (A') = 1 - P (A)

= 1 - 0.015

= 0.985

(A)

Compute the odds that the taxpayer will be audited as follows:

$\text{Odds of being Audited}=\frac{P(A)}{P(A')}$

$=\frac{0.015}{0.985}\\\\=\frac{3}{197}\\\\=0.015228\\\\\approx 0.015$

Thus, the odds that the taxpayer will be audited is approximately 0.015.

(B)

Compute the odds against these taxpayer being audited as follows:

$\text{Odds against Audited}=\frac{P(A')}{P(A)}$

$=\frac{0.985}{0.015}\\\\=\frac{3}{197}\\\\=65.666667\\\\\approx 65.67$

Thus, the odds against these taxpayer being audited is approximately 65.67.

8 0

3 years ago

Mary, Kate, and Sara are playing a card game called Shoe Store. The game is played with 36 cards, which make pairs of shoes. Mar

bekas [8.4K]

The anwser is b 36 divided by 3 is 12

7 0

3 years ago

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

2 years ago

2. Find the value of x.

My name is Ann [436]

Answer:

x = 6

Step-by-step explanation:

3(x + 2) =24

Divide each side by 3

3/3(x+2) = 24/3

x+2 = 8

Subtract 2 from each side

x+2-2 = 8-2

x = 6

4 0

3 years ago

Read 2 more answers

Which of the following correctly factors the expression −20x+4y−2?

Wewaii [24]

9514 1404 393

Answer:

B 2(−10x+2y−1)

Step-by-step explanation:

The greatest common factor is 2. Factoring that out gives the factorization shown in choice B.

2(-10x +2y -1)

You could factor out -2. Doing that would give ...

-2(10x -2y +1) . . . . . . . doesn't match choice C

8 0

2 years ago