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Naddika [18.5K]
3 years ago
15

I need help in my adding and/or subtracting fractions

Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0
First, you have to make sure that two fractions have the same denominator. he best way to do that is:
For Example:     4          7          8          7
                         ----  +  -----  =  -----  +  -----
                         10        20        20        20

Then, just add or subtract the numerators and you got your answer.

Boom.
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the value of x - y is negative an X and Y are both positive what can conclude about the values of X and Y?
tiny-mole [99]

You can conclude that X is smaller than Y. For example:
(2,5)
2 + 5 = 7
2 - 5 = -3

Hope this helped!

3 0
3 years ago
What is 2 2/3×3 1/4 as a fraction form
8090 [49]

Answer:

8 2/3

Step-by-step explanation:

2 2/3×3 1/4

Change to improper fractions.

2 2/3=8/3

3 1/4=13/4

8/3x13/4=26/3

=8 2/3

Hope this helps :)

4 0
2 years ago
Read 2 more answers
(-6.9), (7, -9) find the slope
trasher [3.6K]

Answer:

if you are using point slope formula it will be y = − 6.9 x + 39.3

Step-by-step explanation:

6 0
3 years ago
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what is the median number of car show this month Frank 25, Sarah 20, randall 15, Brahim 22, Alice 20,
Tcecarenko [31]

Answer:

The median is 20.

Step-by-step explanation:

When lined from least to most (15, 20, 20, 22, 25) 20 is the middle number.

4 0
3 years ago
What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers
seraphim [82]

Answer:

Solutions are 2,  -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

or 2,  -1 +  1.58 i  and -1 - 1.58i

(where the last 2 are equal to nearest hundredth).


Step-by-step explanation:

The real solution is x = 2:-

x^3 - 8 = 0

x^3 = 8

x = cube root of 8 = 2

Note that a cubic equation must have  a total of 3 roots ( real and complex in this case).  We can find the 2 complex roots by using the following identity:-

a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here  a = x and b = 2 so we have

(x - 2)(x^2 + 2x + 4) = 0

To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

= -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

4 0
2 years ago
Read 2 more answers
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