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2 years ago

Find Percent of Change1.) 200 to 500. is the answer 40? if not please explain...

Mathematics

2 answers:

BARSIC [14]2 years ago

8 0

Answer: I think it is

Step-by-step explanation:

madreJ [45]2 years ago

7 0

Answer:

150% increase

Step-by-step explanation:

Calculate percentage change

from V1 = 200 to V2 = 500

(V2−V1)|V1|×100

=(500−200)|200|×100

=300200×100

=1.5×100

=150%change

=150%increase

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Write the expression |5x - 4| without absolute value signs

Leokris [45]

Answer:

Step-by-step explanation:

Basically those lines next to the problem are absolute value signs. Get rid of those then your problem is solved.

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2 years ago

A ramp has a horizontal distance of 10 feet and a vertical rise of 3 feet. Find the length of the ramp. Round to the nearest ten

Tatiana [17]

Answer:

Step-by-step explanation:

Tye length of the ramp can be gotten using Pythagoras theorem.

Horizontal distance = 10ft.

Vertical distance = 3ft

Length of the ramp² = 10²+3²

Length of the ramp² = 100+9

Length of the ramp² = 109

L² = 109

L =√109

L = 10.44ft

Hence the length of the ramp is 10.4ft to the nearest tenth

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3 years ago

(x2-13x-48)÷(x+3) dividing polybomials

-BARSIC- [3]

The final awser is x-16
hope this is what u needed

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2 years ago

Find the missing side lengths. Leave your answers as radicals in simplest form

tino4ka555 [31]

We have the triangle 30° - 60° - 90°.

The lenght of the sides are in proportion: $1:2:\sqrt3\to a:2a:a\sqrt3$

$a=y\\2a=x\\a\sqrt3=5\\\\a\sqrt3=5\qquad\text{multiply both sides by}\ \sqrt3\\\\3a=5\sqrt3\qquad\text{divide both sides by 3}\\\\a=\dfrac{5\sqrt3}{3}\\\\2a=2\cdot\dfrac{5\sqrt3}{3}=\dfrac{10\sqrt3}{3}\\\\Answer:\ x=\dfrac{10\sqrt3}{3},\ y=\dfrac{5\sqrt3}{3}$

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3 years ago

Find the exact value of the trigonometric function given that sinU=-7/25 and cosV=-4/5 (Both U and V are in Quadrant III)

Contact [7]

cosU:-

$\\ \rm\longmapsto \sqrt{1-sin^2U}=\sqrt{1-49/625}=24/25$

As U lies in Q3

cosU=-24/25

sinV

$\\ \rm\longmapsto \sqrt{1-cos^2V}=\sqrt{1-16/25}=3/4$

As V lies in Q3

sinV=-3/5

sin(V-U)=sinVcosU-cosVsinU=(-3/5)(-24/25)-(-4/5)(-7/25)=72/125-28/125=72-28/125=44/125
cos(U-V)=cosUcosV+sinUsinV=(-24/25)(-4/5)+(-7/25)(-3/5)=96/125+21/125=117/125

3 0

1 year ago

Find Percent of Change1.) 200 to 500. is the answer 40? if not please explain...​

Find Percent of Change1.) 200 to 500. is the answer 40? if not please explain...