What is the solution of log base of (2x + 3) 125 = 3?

What are the solutions to the equation f(x)=g(x)?

ycow [4]

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7 0

2 years ago

Sugar canes have lengths X that are normally distributed with mean 365.45 cm and standard deviation 4.9 cm what is the probabili

Gemiola [76]

Answer:

The probability of the length of a randomly selected Cane being between 360 and 370 cm P(360 ≤X≤370) = 0.6851

Step-by-step explanation:

step(i):-

Let 'X' be the random Normal variable

mean of the Population = 365.45

Standard deviation of the population = 4.9 cm

Let X₁ = 360

$Z= \frac{x-mean}{S.D}= \frac{360-365.45}{4.9}$

Z₁ = -1.112

Let X₂ = 370

$Z= \frac{x-mean}{S.D}= \frac{370-365.45}{4.9}$

Z₂ = 0.911

Step(ii):-

The probability of the length of a randomly selected Cane being between 360 and 370 cm

P(x₁≤x≤x₂) = P(z₁≤Z≤z₂)

P(360 ≤X≤370) = P(-1.11≤Z≤0.911)

= P(Z≤0.911)-P(Z≤-1.11)

= 0.5 +A(0.911) - (0.5-A(1.11)

= 0.5 +A(0.911) - 0.5+A(1.11)

= A(0.911) + A(1.11)

= 0.3186 + 0.3665

= 0.6851

The probability of the length of a randomly selected Cane being between 360 and 370 cm P(360 ≤X≤370) = 0.6851

5 0

2 years ago

Please help asap WILL GIVE BRAINLIEST

dexar [7]

Sorry I can’t see the picture it’s blurry for me

8 0

3 years ago

Consider the game where two dice, die A and die B, are rolled. We say that die A wins, and write A > B, if the outcome of rol

In-s [12.5K]

Answer:

a) The probability of a tie is the probability of getting the same outcome in both dice.

First, we roll die A and we get a given outcome. (here the probability is 1 because there is no restriction)

Now we need to roll die B and get the same outcome, so here we have only one possible outcome out of 6, then in this case the probability is 1/6

The joint probability (the product of the individual probabilities) is: P = 1*(1/6) = 1/6

b) We want to find the probability that die A wins.

Here we need to analyze each possible outcome for die A.

Let's define:

pₙ = probability of winning given that the outcome is n.

If the outcome is a 1, die A can only lose or tie, then here:

p₁ = 0

If the outcome is a 2, then die A only wins if die B rolls a 1, (1 outcome out of 6)

Then the probability of winning is:

p₂ = 1/6

If the outcome is a 3, then die A wins if die B rolls a 1 or a 2, here we have two possible outcomes out of 6.

p₃ = 2/6

We already can see the pattern, if the outcome is a 4, we get:

p₄ = 3/6

if the outcome is a 5:

p₅ = 4/6

if the outcome is a 6:

p₆ = 5/6

The total probability is the sum of all the joint probabilities:

For each roll in dice A, the probability is 1/6 (the probability of getting a given outcome)

Then the probability that die A wins is:

P = (1/6)*p₁ + (1/6)*p₂ + ... = (1/6)*(p₁ + p₂ + p₃ + p₄ + p₅ + p₆)

P = (1/6)*(0 + 1/6 + 2/6 + 3/6 + 4/6 + 5/6)

P = (1/6)*(15/6) = 0.4167

3 0

3 years ago

Cynthia makes 4 deposits of $50 each and 3 withdrawals of $75 each. What is the total change in Cynthia's account?

scoray [572]

Answer:

$-25

Step-by-step explanation:

(4*50) - (3*75)

200 - 225

-25

8 0

3 years ago

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