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Juli2301 [7.4K]
3 years ago
14

Given that R=2x+9y Find x when y=3 and R=13.

Mathematics
1 answer:
german3 years ago
6 0

R = 2x + 9y [ Given ]

When,

  • y = 3

  • R = 13

★ Substituting the values in the above equation

=> 13 = 2x + 9 × 3

=> 13 = 2x + 27

=> 13 - 27 = 2x

=> -14 = 2x

=> x = -14/2

=> x = -7

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Find the coordinates of P so that P partitions the segment AB in the ratio 6:2 if A(−4,12) and B(9,−4).
Jobisdone [24]

<u>ANSWER</u>

B. (5.75, 0)

<u>EXPLANATION</u>

If the point P(x,y) partitioned

A(x_1,y_1)

and

B(x_2,y_2)

in the ratio m:n, then

x =  \frac{mx_2+nx_1}{m + n}

y=\frac{my_2+ny_1}{m + n}

If the coordinates are A(−4,12) and B(9,−4), then:

x =  \frac{6 \times 9+2 \times  - 4}{6 + 2}

x =  \frac{54 - 8}{8}

x =  \frac{46}{8}

x = 5.75

y=  \frac{6 \times  - 4+2 \times  12}{6 + 2}

y =  \frac{24 - 24}{8}

y =  \frac{0}{24}  = 0

The correct choice is

B. (5.75, 0)

3 0
3 years ago
I need help please and thank you
JulijaS [17]

Answer:

50

Step-by-step explanation:

(14*14)+(48*48)=c2

196+2304=2500

squared root of 2500=50

6 0
3 years ago
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Why did the elephant laugh at Tarzan?
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Answer:

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3 years ago
What are the domain range of f(x)= 1/5 power of x
Snowcat [4.5K]

Answer:

Domain: all real numbers

Range: all real numbers

Step-by-step explanation:

I'm assuming you mean the function f(x)=x^{\frac{1}{5}}.  That's usually written

f(x) = x^(1/5) with the ^ meaning "to the power of..." and the fraction exponent in parentheses so as not to be confused with x^1/5 which could mean x to the first power, divided by 5.

Fractional exponents are used to indicate roots.  In this case, x is being raised to the 1/5 power, so this is the fifth root of x, written \sqrt[5]{x}.  The 5 is called the root index.

For odd roots, like this one, the domain is all real numbers--<em>x</em> can be any number at all.  So the domain is all real numbers.

The range is also all real numbers.  Attached is a graph of this function. It might not look like it, but the graph rises to the right to any height.  The larger <em>x</em> gets, the larger the 5th root gets.  A similar thing happens on the left--the smaller <em>x</em> gets, the smaller the 5th root gets.

EDIT: see the comment.  For the function f(x)=(1/5)^x, the domain is all real numbers. The range is positive real numbers.  I'll attach a graph!

3 0
4 years ago
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Anestetic [448]

Answer:

D.

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<em>please give brainliest</em>

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