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mamaluj [8]
3 years ago
8

A pair of kids and a pair of adults decided to compete in a three-legged race. The kids got to start 4 yards ahead of the adults

, since they had shorter legs. When they were told to start, the kids hobbled forward at a rate of 1 yard per second, and the adults hobbled after them at a rate of 2 yards per second. Soon they were side-by-side. How far did the adults go?
Mathematics
1 answer:
andrew-mc [135]3 years ago
4 0
Use the y=mx+b Format
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juan needs to measure 6 cups of flour for a recipe.he only has a 1/4 cup measuring cup.how many times must he fill the measuring
Luba_88 [7]

Answer:

Juan would need to fill up the 1/4 measuring cup 24 times.

Step-by-step explanation:

So to measure one cup of flour with a 1/4 measuring cup, you would need to fill up the 1/4 measuring cup 4 times. Since we want 6 cups, you would need to fill up the 1/4 measuring cup 24 times. 6 times 4 = 24. Hope this helps!

7 0
3 years ago
What is the solution to the following system?<br> -4y=8 <br> x+3y-3z=-26<br> 2x-5y+z=19
Viktor [21]
⓵
-4ỿ = 8

Simplify the left side in order to isolate the ỿ!

-4ỿ = 8
+4 +4

Ỿ = 12

⓶
× + 3y - 3z = -26

Simplify the left side in order to isolate the ×, ỿ and z!

× + 3y - 3z = -26
÷3 ÷3

× + ỿ - 3z = -8,66 periodic
÷-3 ÷-3

× + ỿ + z = 2,88 periodic

⓷
2× - 5ỿ + z = 19

Simplify the left side in order to isolate the ×, ỿ and z!

2× - 5ỿ + z = 19
÷2 ÷2

× - 5ỿ + z = 9,5
÷-5 ÷-5

× + ỿ + z = -1,9
3 0
3 years ago
Read 2 more answers
Round 8.275 to the nearest tenth of an ounce
Helen [10]

Answer:

8.3

Step-by-step explanation:

The tenths spot in 8.275 is where the 2 is. Since it is a 75 after that you will round it up.

. Tenths (2), Hundredths (7), Thousandths (5)

8 0
3 years ago
Read 2 more answers
PLEASE HELP NEED THE ANSWER IMMEDIATELY!
vesna_86 [32]

\textsf{\qquad\qquad\huge\underline{{\sf Answer}}}

Volume of a rectangular prism is ~

\sf{Volume_{cuboid}= Length × Width × Height}

\qquad \sf  \dashrightarrow \: v = (4x + 2) \times (3x - 5) \times (7x + 4)

\qquad \sf  \dashrightarrow \: v = (12 {x}^{2} - 20x + 6x - 10) \times (7x + 4)

\qquad \sf  \dashrightarrow \: v = (12 {x}^{2} - 14x- 10) \times (7x + 4)

\qquad \sf  \dashrightarrow \: v = 84 {x}^{3}  + 48 {x}^{2}  - 98x {}^{2}  - 56x - 70x - 40

\qquad \sf  \dashrightarrow \: v = 84 {x}^{3} - 50 {x}^{2}  -  126x - 40

So, the correct choice is B

7 0
2 years ago
A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0
3 years ago
Read 2 more answers
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