3 years ago

HELP!! What is the exponential regression equation that fits these data?

Mathematics

2 answers:

zzz [600]3 years ago

8 0

Answer is b i believe

Alla [95]3 years ago

8 0

Answer:

A. y=3.80*2.01^x

Step-by-step explanation:

a-pex

You might be interested in

At a school carnival, 33 out of 55 tickets sold were early-admission tickets. What percentage of the tickets were early-admissio

7nadin3 [17]

Answer:

60%

Step-by-step explanation:

33/55 = .6

multiple by 100 to convert the decimal into a percentage

.6 × 100 = 60%

8 0

3 years ago

The student setup 30 games booths;the teachers also setup some. If 5/6 of the game booths were set up by the students, how many

Ket [755]

25 were set up by the students

6 0

3 years ago

A manufacturer of radial tires for automobiles has extensive data to support the fact that the lifetime of their tires follows a

Diano4ka-milaya [45]

Answer: (C) 0.1591

Step-by-step explanation:

Given : A manufacturer of radial tires for automobiles has extensive data to support the fact that the lifetime of their tires follows a normal distribution with

$\mu=42,100\text{ miles}$

$\sigma=2,510\text{ miles}$

Let x be the random variable that represents the lifetime of the tires .

z-score : $z=\dfrac{x-\mu}{\sigma}$

For x= 44,500 miles

$z=\dfrac{44500-42100}{2510}\approx0.96$

For x= 48,000 miles

$z=\dfrac{48000-42100}{2510}\approx2.35$

Using the standard normal distribution table , we have

The p-value : $P(44500$

$P(z$

Hence, the probability that a randomly selected tire will have a lifetime of between 44,500 miles and 48,000 miles = 0.1591

3 0

3 years ago

This is a payslip of Mr. Dube a48 years old male employee of a major clothing company

DiKsa [7]

Answer:

where's the payslip dear

8 0

2 years ago

Provide an appropriate response. In order to efficiently bid on a contract, a contractor wants to be 95% confident that his erro

lidiya [134]

Answer:

d. 20

Step-by-step explanation:

Standard deviation is 4.5

Margin error for the problem is 2 hours

Probability 95%, that means that the siginficance level α is 1 – p

α = 1 – 0.95 = 0.05

margin of error (ME) can be defined as follows

ME = Z(α/2) * standard deviation/ √n

Where n is the sample size

Z(0.05/2) = Z(0.025)

Using a z table Z = 1.96

Now, replacing in the equation and find n

2 = 1.96 * 4.5/ √n

2 = 8.82/√n

√n = 8.82/2

√n = 4.41

n = 4.41^2

n = 19.44 ≈ 20

5 0

2 years ago