Brian "bicycle kicked" a soccer ball up from a height of 4ft off the ground with an initial upward velocity of 34 feet/sec. As t he ball was coming down, Mike jumped up and at 8 ft off the ground, headed it into the goal and win the game. How long did it take for the ball to come down and reach Mike's head?
1 answer:
Answer:
1.95 seconds or 2.06 seconds
(Depending on your acceleration value)
Step-by-step explanation:
s = ut + 0.5at²
u = 34 ft/s
a = -10 m/s² = -32.8084 ft/s²
s = 8-4 = 4 ft
4 = 34t + ½(-32.8084)t²
4 = 34t - 16.4042t²
16.4042t² - 34t + 4 = 0
t = 1.946, 0.125
Mike catches the ball the second time it was at a height of 8ft.
Do t = 1.95 s
If you use a = 32.17405 ft/s²,
t = 2.05655765 (2.06 seconds in 3 sf)
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