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Vinil7 [7]
3 years ago
9

The sum of three consecutive numbers is 537. What is the 3rd number?

Mathematics
1 answer:
maks197457 [2]3 years ago
8 0

For this problem your equation will be x+(x+1)+(x+2)=537

Multiply and Simplify:

x+x+1+x+2=537

3x+3=537

Subtract 3 from both sides:

3x+3-3=537-3

3x=534

Divide both sides by 3:

3x/3=537/3

x=179

179 is the middle number so: 178+179+180=537

180 is the third number.



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Let f(x) = - 13x + 12 and g(x)= x² + 2.--Find f(3)/g(3).f(3)/g(3) = (?)(Type an integer or a simplified fraction.)
mel-nik [20]

We have the next two equations:

f(x)=-13x+12

And

g(x)=x^2+2

We need to find f(3)/g(3)

First, let's find f(3):

f(3)\text{ = -13(3)+12 = -27}

Then g(3):

g(3)=(3)^2+2\text{ = 11}

Now, the equation f(3)/g(3) :

\frac{f(3)}{g(3)}=\frac{-27}{11}

-27/11 is the result.

3 0
2 years ago
Which of the following is the best approximation of the volume of a sphere with a 9 cm radius?
LenaWriter [7]
Volume = 4/3 * PI * r^3
Volume = 4/3 * 3.14159 * 9^3
Volume = <span> <span> <span> 4.18879 * 729
</span></span></span>Volume = <span> <span> <span> 3,053.62 cubic centimeters

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5 0
3 years ago
Rachel has a bag of fruit that has a mass of 50 hectograms. Rachel converts this mass to centigrams. Her work is shown below.
Alinara [238K]

Answer:

She should have multiplied by 10,000

Step-by-step explanation:

Given table:

\begin{array}{| c | c |}\cline{1-2} \sf kilo & 1,000 \\\cline{1-2} \sf hecto & 100 \\\cline{1-2} \sf deka & 10 \\\cline{1-2} \sf unit & 1 \\\cline{1-2} \sf deci & 0.1 \\\cline{1-2} \sf centi & 0.01 \\\cline{1-2} \sf milli & 0.001 \\\cline{1-2}\end{array}

To find the conversion rate:

\sf \dfrac{hecto}{centi}=\dfrac{100}{0.01}=10000

Therefore, 1 hectogram = 10,000 centigrams

So when converting hectograms to centigrams, multiply the mass by 10,000.

⇒ 50 hg × 10,000 = 500,000 centigrams

Rachel's error was that she should have multiplied by 10,000.

7 0
2 years ago
Read 2 more answers
Add.<br> (3х – 4) + (4х – 6)<br><br> А. 7х+ 10<br> В. 7х+2<br> C. 7х- 2<br> D. 7x - 10
LuckyWell [14K]

Answer:

D

Step-by-step explanation:

Because you have to do work

3 0
3 years ago
Passing through (2, - 2) and perpendicular to the line whose equation is y= 5x+2
jonny [76]

Step-by-step explanation:

Hey there!!!

Here,

Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.

The equation of a straight line passing through point is,

(y - y1) = m1(x - x1)

Now, put all values.

(y  + 2) = m1(x - 2)

It is the 1st equation.

Another equation is;

y = 5x +2........(2nd equation).

Now, Comparing it with y = mx + c, we get;

m2=5

As per the condition of perpendicular lines,

m1×m2= -1

m1 × 5 = -1

Therefore, m2= -1/5.

Keeping the value of m1 in 1st equation.

(y + 2) =  \frac{ - 1}{5} (x - 2)

Simplify them.

5(y + 2) =  - x + 2

5y + 10 =  - x + 2

x + 5y + 8 = 0

Therefore the required equation is x+5y+8= 0.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
4 years ago
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