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Mashcka [7]
3 years ago
6

Which of the following sets of numbers could not represent the three sides of a right triangle?

Mathematics
1 answer:
umka21 [38]3 years ago
7 0

Answer:

{48, 64, 81}

Step-by-step explanation:

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60 to the negative 3 power

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-1/6 + 2/3 ( 9 + - 3/4) + - 1/2
Liono4ka [1.6K]
First simplify the section in the parenthesis. 
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A portion of the Quadratic Formula proof is shown. Fill in the missing statement.
Zielflug [23.3K]

Answer:

Option A.

Step-by-step explanation:

we have

x+\frac{b}{2a} =\pm\sqrt{\frac{b^2-4ac}{4a^2}}

Simplify the right side of the equation

we know that

\pm\sqrt{\frac{b^2-4ac}{4a^2}}=\pm\frac{\sqrt{b^2-4ac}}{\sqrt{4a^2}}=\pm\frac{\sqrt{b^2-4ac}}{2a}

so

The expression is

x+\frac{b}{2a}=\pm\frac{\sqrt{b^2-4ac}}{2a}

therefore

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

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How do you solve this question?
dezoksy [38]

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3 years ago
Which expression can be used to determine the length of segment AB? On a coordinate plane, triangle A B C has points (4, 3), (ne
JulijaS [17]

Answer:

StartRoot 2 squared + 6 squared EndRoot

Step-by-step explanation:

we have

A(4,3) and B(-2,1)

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the given values

AB=\sqrt{(1-3)^{2}+(-2-4)^{2}}

AB=\sqrt{(-2)^{2}+(-6)^{2}}

AB=\sqrt{40}\ units

therefore

StartRoot 2 squared + 6 squared EndRoot

7 0
3 years ago
Read 2 more answers
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