h = 50 cos ( pie(x - 10 )/15 ) + 52
80 = 50 cos ( pie( x - 10 )/15 ) + 52
80 - 52 = 50 cos ( pie( x - 10 )/15 )
28 = 50 cos ( pie( x - 10 )/15 )
cos ( pie( x - 10 )/15 ) = 28/50
cos ( pie( x - 10 )/15 ) = 56/100
cos ( pie( x - 10 )/15 ) = cos ( 56 )
cos ( pie( x - 10 )/15 ) = cos ( 0.3111 pie )
Thus ;
pie( x - 10 )/15 = 0.3111 pie
( x - 10 )/15 = 0.3111
x - 10 = 15 × 0.3111
x - 10 = 4.6665
x = 10 + 4.6665
x = 14.6665 [ approximately ]
Thus the correct answer is exactly what u chose goodjob .....
Angle B is also 54° because they are vertically opposite angles.
Now, you do 54+54=108 and then 360-108=252. (The angles should always add up to 360, so remember that) Because angles C and D are also vertically corresponding angles, they add up to 252, and each measure 126°
Recall your d = rt, distance = rate * time
thus
![\bf \begin{array}{lccclll} &distance&rate&time(hrs)\\ &-----&-----&-----\\ \textit{first car}&d&55&x\\ \textit{second car}&380-d&75&x+1 \end{array}\\\\ -----------------------------\\\\ \begin{cases} \boxed{d}=(55)(x)\\\\ 380-d=(75)(x+1)\\ ----------\\ 380-\left( \boxed{(55)(x)} \right)=(75)(x+1) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blccclll%7D%0A%26distance%26rate%26time%28hrs%29%5C%5C%0A%26-----%26-----%26-----%5C%5C%0A%5Ctextit%7Bfirst%20car%7D%26d%2655%26x%5C%5C%0A%5Ctextit%7Bsecond%20car%7D%26380-d%2675%26x%2B1%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%0A%5Cbegin%7Bcases%7D%0A%5Cboxed%7Bd%7D%3D%2855%29%28x%29%5C%5C%5C%5C%0A380-d%3D%2875%29%28x%2B1%29%5C%5C%0A----------%5C%5C%0A380-%5Cleft%28%20%5Cboxed%7B%2855%29%28x%29%7D%20%5Cright%29%3D%2875%29%28x%2B1%29%0A%5Cend%7Bcases%7D)
notice, the first car leaves at "x" time, the other leaves on hour later, or x + 1
the first car travels some distance "d", whatever that is, thus
the second car, picks up the slack, or the difference, they're 380 miles
apart, thus the difference is 380-d
Answer:
-11 and -7
Step-by-step explanation: