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bonufazy [111]
3 years ago
5

Solve the inequality. Enter the answer as an inequality that shows the value of the variable; for example f > 7, or 6 < w.

Where necessary, use <= to write and use >= to write . 25 + x < -40
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
Subtract 25.
  25 - 25 + x < -40 - 25
Simplify
  x < -65

_____
An inequality is solved exactly the same way an equation is solved, with one exception.‡ Multiplying or dividing by a negative number reverses the sense of the inequality:
  2 > 1
  -2 < -1 . . . . multiplied by -1


___
‡ The exception can be generalized to the use of any function that reverses the ordering of its arguments. In Algebra, about the only function we use that has negative slope is the cosine function (and its inverse). You rarely see these used in inequalities.
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I need help on it, I don’t know what I’m supposed to do
bogdanovich [222]

Answer:

The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.

Step-by-step explanation:

See the attached diagram.

The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.

Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45

Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x

So, (42x + 43x + 44x + 45x) = 400

⇒ 175x = 400

⇒ x = 2.2988.

So, PQ = 42x = 96.55 ft.

QR = 43x = 98.85 ft.

RS = 44x = 101.15 ft and  

ST = 45x = 103.45 ft

(Answer)

6 0
3 years ago
If you are given three sides of a triangle, you would use the law of
miv72 [106K]
You would use the law of cosines
7 0
3 years ago
fire work a travels at the speed 300 ft/s firework b travels 240 ft/s. firework b is launched 0.25s before firework a. how many
storchak [24]

Answer:

Both fireworks  will explode after 1 seconds after firework b launches.

Step-by-step explanation:

Given:

Speed of fire work A= 300 ft/s

Speed of Firework B=240 ft/s

Time before which fire work b is launched =0.25s

To Find:

How many seconds after firework b launches will both fireworks explode=?

Solution:

Let t be the time(seconds) after which both the fireworks explode.

By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation

Firework A= 330(t)

Firework B=240(t)+240(0.25)

Since we need to know the same time after which they explode, we can equate both the equations

330(t) = 240(t)+240(0.25)

300(t)= 240(t)+60

300(t)-240(t)= 60

60(t)=60

t=\frac{60}{60}

t=1

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3 years ago
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To Simplify Fractions what you have to do is get the number then see what can divide into both the numerator and denominator equally Here:

1.5/8 Nothing can go into both so you leave it.

2. 3/5 + 1/4 = 4/9 Still nothing can go into it.

3. 4/7 + 1/8 = 5/15 you can divide, 5 can go into 5 , 1 time , 5 can go into 15    3 times the answer is 1/3
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At the end of last year mark odometer reads 74,924 miles.at the end of this year , his odometer. reads 90,405 miles. How many mi
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Mark drove 165,329 miles year
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